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Select the correct option from the given alternatives: Centre of the ellipse 9x2 + 5y2 − 36x − 50y − 164 = 0 is at - Mathematics and Statistics

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प्रश्न

Select the correct option from the given alternatives:

Centre of the ellipse 9x2 + 5y2 − 36x − 50y − 164 = 0 is at

विकल्प

  • (2, 5)

  • (1, −2)

  • (−2, 1)

  • (0, 0)

MCQ
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उत्तर

(2, 5)

Explanation:

The given equation can be written as:

(9x2 – 36x) + (5y2 – 50y) = 164

∴ 9(x2 – 4x + 4) + 5(y2 – 10y + 25) = 164 + 36 + 125

∴ 9(x – 2)2 + 5(y – 5)2 = 325

∴ `("x" - 2)^2/((325/9)) + ("y" - 5)^2/65` = 1

This is of the form `"X"^2/"a"^2 + "Y"^2/"b"^2` = 1, where X = x – 2, Y = y – 5.

∴ centre of the ellipse is given by

X = x – 2 = 0 and Y = y – 5 = 0

∴ x = 2, y = 5

∴ centre = (2, 5)

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Conic Sections - Ellipse
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Conic Sections - Miscellaneous Exercise 7 [पृष्ठ १७७]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 7 Conic Sections
Miscellaneous Exercise 7 | Q I. (18) | पृष्ठ १७७

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