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Answer the following: Find the equation of the tangent to the ellipse x2 + 4y2 = 100 at (8, 3)

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प्रश्न

Answer the following:

Find the equation of the tangent to the ellipse x2 + 4y2 = 100 at (8, 3)

योग
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उत्तर

Given equation of ellipse is x2 + 4y2 = 100

 ∴ `x^2/100 + y^2/25` = 1

Comparing this equation with `x^2/"a"^2 + y^2/"b"^2` = 1, we get

a2 = 100 and b2 = 25

Equation of tangent to the ellipse

`x^2/"a"^2 + y^2/"b"^2` = 1

at (x1, y1) is `("xx"_1)/"a"^2 + (yy_1)/"b"^2` = 1

∴ Equation of tangent at (8, 3) is

`(8x)/100 + (3y)/25` = 1

∴ `(2x)/25 + (3y)/25` = 1

∴ 2x + 3y = 25.

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अध्याय 7: Conic Sections - Miscellaneous Exercise 7 [पृष्ठ १७८]

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बालभारती Mathematics and Statistics (Arts and Science) Part 1 [English] Standard 11 Maharashtra State Board
अध्याय 7 Conic Sections
Miscellaneous Exercise 7 | Q 2.18 | पृष्ठ १७८

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Answer the following:

Find the

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  2. co-ordinates of the foci
  3. equations of directrices
  4. length of the latus rectum
  5. distance between foci
  6. distance between directrices of the ellipse:

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  3. equations of directrics
  4. length of the latus rectum
  5. distance between focii
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  3. equations of directrics 
  4. length of the latus rectum
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