हिंदी

Find the equation of the tangent to the ellipse x2 + 4y2 = 20, ⊥ to the line 4x + 3y = 7.

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प्रश्न

Find the equation of the tangent to the ellipse x2 + 4y2 = 20, ⊥ to the line 4x + 3y = 7.

योग
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उत्तर

Given equation of the ellipse is x2 + 4y2 = 20.

∴ `x^2/20 + y^2/5` = 1

Comparing this equation with `x^2/"a"^2 + y^2/"b"^2` = 1, we get

a2 = 20 and b2 = 5

Slope of the given line 4x + 3y = 7 is `(-4)/3`.

Since the given line is perpendicular to the required tangents, slope of the required tangents is m = `3/4`.

Equations of tangents to the ellipse

`x^2/"a"^2 + y^2/"b"^2` = 1 having slope m are

y = `"m"x ± sqrt("a"^2"m"^2 + "b"^2)`

∴ y = `3/4x ± sqrt(20(3/4)^2 + 5)`

∴ y = `3/4x ± sqrt(45/4 + 5)`

∴ y = `3/4x ± sqrt(65)/2`

∴ 4y = `3x ± 2sqrt(65)`

∴ 3x – 4y = `±2sqrt(65)`

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अध्याय 7: Conic Sections - Exercise 7.2 [पृष्ठ १६३]

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बालभारती Mathematics and Statistics (Arts and Science) Part 1 [English] Standard 11 Maharashtra State Board
अध्याय 7 Conic Sections
Exercise 7.2 | Q 11. (vii) | पृष्ठ १६३

संबंधित प्रश्न

Answer the following:

Find the

  1. lengths of the principal axes
  2. co-ordinates of the foci
  3. equations of directrices
  4. length of the latus rectum
  5. distance between foci
  6. distance between directrices of the ellipse:

`x^2/25 + y^2/9` = 1


Find the 

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  2. co-ordinates of the focii 
  3. equations of directrices 
  4. length of the latus rectum
  5. distance between focii 
  6. distance between directrices of the ellipse:

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