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प्रश्न
Extend the definition of the following by continuity
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उत्तर
Given:
If f(x) is continuous at x =
\[ \Rightarrow \lim_{x \to \pi} \frac{1 - \cos7\left( x - \pi \right)}{5 \left( x - \pi \right)^2} = f\left( \pi \right)\]
\[ \Rightarrow \frac{2}{5} \lim_{x \to \pi} \frac{\sin^2 \left( \frac{7\left( x - \pi \right)}{2} \right)}{\left( x - \pi \right)^2} = f\left( \pi \right)\]
\[ \Rightarrow \frac{2}{5} \times \frac{49}{4} \lim_{x \to \pi} \frac{\sin^2 \left( \frac{7\left( x - \pi \right)}{2} \right)}{\frac{49}{4} \left( x - \pi \right)^2} = f\left( \pi \right)\]
\[ \Rightarrow \frac{2}{5} \times \frac{49}{4} \lim_{x \to \pi} \frac{\sin^2 \left( \frac{7\left( x - \pi \right)}{2} \right)}{\left( \frac{7}{2}\left( x - \pi \right) \right)^2} = f\left( \pi \right)\]
\[ \Rightarrow \frac{2}{5} \times \frac{49}{4} \lim_{x \to \pi} \left[ \frac{\sin\left( \frac{7\left( x - \pi \right)}{2} \right)}{\left( \frac{7}{2}\left( x - \pi \right) \right)} \right]^2 = f\left( \pi \right)\]
\[ \Rightarrow \frac{2}{5} \times \frac{49}{4} \times 1 = f\left( \pi \right)\]
\[ \Rightarrow \frac{1}{5} \times \frac{49}{2} \times 1 = f\left( \pi \right)\]
\[ \Rightarrow \frac{49}{10} = f\left( \pi \right)\]
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