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If F ( X ) = 2 X + 3 Sin X 3 X + 2 Sin X , X ≠ 0 If F(X) is Continuous at X = 0, Then Find F (0).

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प्रश्न

If  \[f\left( x \right) = \frac{2x + 3\ \text{ sin }x}{3x + 2\ \text{ sin }  x}, x \neq 0\] If f(x) is continuous at x = 0, then find f (0).

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उत्तर

Given: 

\[f\left( x \right) = \frac{2x + 3\sin x}{3x + 2\sin x}, x \neq 0\]

\[\lim_{x \to 0} f\left( x \right) = f\left( 0 \right)\]
\[ \Rightarrow \lim_{x \to 0} \frac{2x + 3\ sinx}{3x + 2\ sinx} = f\left( 0 \right)\]
\[ \Rightarrow \lim_{x \to 0} \frac{x\left( 2 + 3\frac{\ sinx}{x} \right)}{x\left( 3 + 2\frac{\ sinx}{x} \right)} = f\left( 0 \right)\]
\[ \Rightarrow \lim_{x \to 0} \frac{\left( 2 + 3\frac{\ sinx}{x} \right)}{\left( 3 + 2\frac{\ sinx}{x} \right)} = f\left( 0 \right)\]
\[ \Rightarrow \frac{\lim_{x \to 0} \left( 2 + 3\frac{\ sinx}{x} \right)}{\lim_{x \to 0} \left( 3 + 2\frac{\ sinx}{x} \right)} = f\left( 0 \right)\]
\[ \Rightarrow \frac{2 + 3 \lim_{x \to 0} \left( \frac{\ sinx}{x} \right)}{3 + 2 \lim_{x \to 0} \left( \frac{\ sinx}{x} \right)} = f\left( 0 \right)\]
\[ \Rightarrow \frac{2 + 3 \times 1}{3 + 2 \times 1} = f\left( 0 \right)\]
\[ \Rightarrow \frac{5}{5} = f\left( 0 \right)\]
\[ \Rightarrow f\left( 0 \right) = 1\]

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अध्याय 8: Continuity - Exercise 9.1 [पृष्ठ २०]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 8 Continuity
Exercise 9.1 | Q 34 | पृष्ठ २०

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