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Determine Whether F ( X ) = ( Sin X 2 X , X ≠ 0 0 , X = 0 ) is Continuous at X = 0 Or Not.

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प्रश्न

Determine whether \[f\left( x \right) = \binom{\frac{\sin x^2}{x}, x \neq 0}{0, x = 0}\]  is continuous at x = 0 or not.

 

योग
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उत्तर

Given: 

\[f\left( x \right) = \binom{\frac{\sin x^2}{x}, x \neq 0}{0, x = 0}\]
We have 

\[\lim_{x \to 0} f\left( x \right) = \lim_{x \to 0} \frac{\sin x^2}{x}\]

                \[ = \lim_{x \to 0} \frac{x \sin x^2}{x^2}\]

               \[ = \lim_{x \to 0} \frac{\sin x^2}{x^2}  \lim_{x \to 0} x\]

               \[ = 1 \times 0\]

              \[ = 0\]

              \[ = f\left( 0 \right)\]

\[\therefore \lim_{x \to 0} f\left( x \right) = f\left( 0 \right)\]

Hence

\[f\left( x \right)\]  is continuous at  \[x = 0\] . 
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अध्याय 8: Continuity - Exercise 9.3 [पृष्ठ ४२]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 8 Continuity
Exercise 9.3 | Q 7 | पृष्ठ ४२

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