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Is the function defined by f(x) = x2 − sin x + 5 continuous at x = π?

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प्रश्न

Is the function defined by f(x) = x2 − sin x + 5 continuous at x = π?

योग
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उत्तर

f(x) = x2 − sin (x) + 5

If f(x) is continuous at x = π, it implies:

f(π) = `lim_(x -> pi^+)` f(x) = `lim _(x -> pi^-)` f(x)

⇒ (π2 − sin (π) + 5) = (π2 − sin (π) + 5) = (π2 − sin (π) + 5)

⇒ π2 + 5 = π2 + 5 = π2 + 5

Which is true, i.e., f(x) is continuous at x = π.

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अध्याय 5: Continuity and Differentiability - Exercise 5.1 [पृष्ठ १६०]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 5 Continuity and Differentiability
Exercise 5.1 | Q 20 | पृष्ठ १६०

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