हिंदी

Differentiate the following w.r.t.x: tanx - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Differentiate the following w.r.t.x: `sqrt(tansqrt(x)`

योग
Advertisements

उत्तर

Let y = `sqrt(tansqrt(x)`
Differentiating w.r.t. x,we get,
`"dy"/"dx" = "d"/"dx"(sqrt(tansqrt(x)))`

= `1/(2sqrttansqrt(x))."d"/"dx"(tansqrt(x))`

= `1/(2sqrttansqrt(x)) xx sec^2sqrt(x)."d"/"dx"(sqrt(x))`

= `1/(2sqrttansqrt(x)) xx sec^2sqrt(x) xx 1/(2sqrt(x)`

= `sec^2sqrt(x)/(4sqrt(x)sqrt(tansqrt(x)`.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1: Differentiation - Exercise 1.1 [पृष्ठ १२]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 1 Differentiation
Exercise 1.1 | Q 2.04 | पृष्ठ १२

संबंधित प्रश्न

Differentiate the following w.r.t. x:

(x3 – 2x – 1)5


Differentiate the following w.r.t.x: cos(x2 + a2)


Differentiate the following w.r.t.x:

`sqrt(e^((3x + 2) +  5)`


Differentiate the following w.r.t.x: `5^(sin^3x + 3)`


Differentiate the following w.r.t.x: `"cosec"(sqrt(cos x))`


Differentiate the following w.r.t.x: log[cos(x3 – 5)]


Differentiate the following w.r.t.x: `e^(3sin^2x - 2cos^2x)`


Differentiate the following w.r.t.x: sec[tan (x4 + 4)]


Differentiate the following w.r.t.x: [log {log(logx)}]2


Differentiate the following w.r.t.x:

sin2x2 – cos2x2 


Differentiate the following w.r.t.x:

(x2 + 4x + 1)3 + (x3− 5x − 2)4 


Differentiate the following w.r.t.x:

log (sec 3x+ tan 3x)


Differentiate the following w.r.t.x: `cot(logx/2) - log(cotx/2)`


Differentiate the following w.r.t.x:

`(e^(2x) - e^(-2x))/(e^(2x) + e^(-2x))`


Differentiate the following w.r.t.x: log[tan3x.sin4x.(x2 + 7)7]


Differentiate the following w.r.t.x: `log(sqrt((1 - sinx)/(1 + sinx)))`


Differentiate the following w.r.t.x:

`log[a^(cosx)/((x^2 - 3)^3 logx)]`


Differentiate the following w.r.t. x : tan–1(log x)


Differentiate the following w.r.t. x : cot–1(x3)


Differentiate the following w.r.t. x : `sin^4[sin^-1(sqrt(x))]`


Differentiate the following w.r.t. x : `"cosec"^-1[1/cos(5^x)]`


Differentiate the following w.r.t. x : `sin^-1((4sinx + 5cosx)/sqrt(41))`


Differentiate the following w.r.t. x : `tan^-1((2x)/(1 - x^2))`


Differentiate the following w.r.t. x : cos–1(3x – 4x3)


Differentiate the following w.r.t. x : `tan^-1((8x)/(1 - 15x^2))`


Differentiate the following w.r.t. x : `cot^-1((a^2 - 6x^2)/(5ax))`


Differentiate the following w.r.t. x :

`tan^-1((5 -x)/(6x^2 - 5x - 3))`


Differentiate the following w.r.t. x : `cot^-1((4 - x - 2x^2)/(3x + 2))`


Differentiate the following w.r.t. x: xe + xx + ex + ee.


Differentiate the following w.r.t. x : (logx)x – (cos x)cotx 


Differentiate the following w.r.t. x : `x^(e^x) + (logx)^(sinx)`


Differentiate the following w.r.t. x : `10^(x^(x)) + x^(x(10)) + x^(10x)`


Show that `"dy"/"dx" = y/x` in the following, where a and p are constants : x7.y5 = (x + y)12 


Show that `"dy"/"dx" = y/x` in the following, where a and p are constants : `cos^-1((7x^4 + 5y^4)/(7x^4 - 5y^4)) = tan^-1a`


Show that `"dy"/"dx" = y/x` in the following, where a and p are constants : `e^((x^7 - y^7)/(x^7 + y^7)` = a


If y is a function of x and log (x + y) = 2xy, then the value of y'(0) = ______.


If f(x) is odd and differentiable, then f′(x) is


If y = `sin^-1[("a"cosx - "b"sinx)/sqrt("a"^2 + "b"^2)]`, then find `("d"y)/("d"x)`


Derivative of (tanx)4 is ______ 


A particle moves so that x = 2 + 27t - t3. The direction of motion reverses after moving a distance of ______ units.


The differential equation of the family of curves y = `"ae"^(2(x + "b"))` is ______.


Let f(x) = `(1 - tan x)/(4x - pi), x ne pi/4, x ∈ [0, pi/2]`. If f(x) is continuous in `[0, pi/2]`, then f`(pi/4)` is ______.


The volume of a spherical balloon is increasing at the rate of 10 cubic centimetre per minute. The rate of change of the surface of the balloon at the instant when its radius is 4 centimetres, is ______


Differentiate `tan^-1 (sqrt((3 - x)/(3 + x)))` w.r.t. x.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×