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Differentiate the following w.r.t.x: cosx+cosx - Mathematics and Statistics

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प्रश्न

Differentiate the following w.r.t.x:

`sqrt(cosx) + sqrt(cossqrt(x)`

योग
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उत्तर

Let y = `sqrt(cosx) + sqrt(cossqrt(x)`
Differentiating w.r.t. x, we get
`"dy"/"dx" = "d"/"dx"[sqrt(cosx) + sqrt(cossqrt(x))]`

= `"d"/"dx"(cosx)^(1/2) + "d"/"dx"(cossqrt(x))^(1/2)`

= `1/2(cosx)^(-1/2)."d"/"dx"(cosx) + 1/2(cossqrt(x))^(-1/2)."d"/"dx"(cossqrt(x))`

= `(1)/(2sqrt(cosx)).(-sinx) + (1)/(2sqrt(cossqrt(x))) xx (-sinsqrt(x))."d"/"dx"(sqrt(x))`

= `(-sinx)/(2sqrt(cosx)) - (sinsqrt(x))/(2sqrt(cossqrt(x))) xx (1)/(2sqrt(x)`

= `(-sinx)/(2sqrt(cosx)) - (sinsqrt(x))/(4sqrt(x)sqrt(cossqrt(x)`

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Differentiation
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1: Differentiation - Exercise 1.1 [पृष्ठ १२]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 1 Differentiation
Exercise 1.1 | Q 3.06 | पृष्ठ १२

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