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Differentiate the following w.r.t. x: xtan-1x

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प्रश्न

Differentiate the following w.r.t. x: `x^(tan^(-1)x`

योग
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उत्तर

Let y = `x^(tan^(-1)x`

Then log y = `log (x^(tan^(-1)x)) = (tan^-1 x)(logx)`

Differentiating both sides w.r.t. x, we get

`(1)/y.(dy)/(dx) = d/(dx)[(tan^-1 x)(logx)]`

= `(tan^-1 x).d/(dx)(logx) + (logx).d/(dx)(tan^-1 x)`

= `(tan^-1 x) xx 1/x + (logx) xx 1/(1 + x^2)`

∴ `(dy)/(dx) = y[(tan^-1 x)/x + logx/(1 + x^2)]`

= `x^(tan^-1 x)[tan^-1 x/x + logx/(1 + x^2)]`

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अध्याय 1: Differentiation - Exercise 1.3 [पृष्ठ ३९]

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