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Show that dydxdydx=yx in the following, where a and p are constants : sin(x3-y3x3+y3) = a3

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प्रश्न

Show that `"dy"/"dx" = y/x` in the following, where a and p are constants : `sin((x^3 - y^3)/(x^3 + y^3))` = a3 

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उत्तर

`sin((x^3 - y^3)/(x^3 + y^3))` = a3 

`(x^3 - y^3)/(x^3 + y^3)` = sina3 = b

`(x^3 - y^3)/(x^3 + y^3)` = b

x3 – y3 = b(x3 + y3)
x3 – y3 = bx3 + by3
x3 – bx3 = by3 + y3
x3(1 – b) = y3(b + 1)
`y^3/x^3 = (1 - b)/(1 + b)` = e

`y^3/x^3` = c   .....(1)
y3 = cx3
Differentiating both sides w.r.t. x, we get
`3y^2"dy"/"dx"` = c.3x2

`(y^2dy)/(dx)` = cx2

`"dy"/"dx" c x^2/y^2`

`"dy"/"dx" = y^3/x^3. x^2/y^2` ....from(1)

`"dy"/"dx" = y/x`.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1: Differentiation - Exercise 1.3 [पृष्ठ ४०]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 1 Differentiation
Exercise 1.3 | Q 4.8 | पृष्ठ ४०

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