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Differentiate the following w.r.t.x: e(3x+2)+ 5 - Mathematics and Statistics

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प्रश्न

Differentiate the following w.r.t.x:

`sqrt(e^((3x + 2) +  5)`

योग
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उत्तर

Let y = `sqrt(e^((3x + 2) +  5)`
Differentiating w.r.t. x,we get,
`"dy"/"dx" = "d"/"dx"[e^((3x + 2)) + 5]^(1/2)`

= `1/2[e^((3x + 2)) + 5]^(-1/2)."d"/"dx"[e^((3x + 2)) + 5]`

= `1/(2sqrt(e^((3x + 2)) + 5)).[e^((3x + 2)). "d"/"dx"(3x + 2)  +  0]`

= `1/(2sqrt(e^((3x + 2)) + 5)).[e^((3x + 2)). (3 xx 1 + 0)]`

= `(3e^((3x + 2)))/(2sqrt(e^((3x + 2))+ 5)`.

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Differentiation
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1: Differentiation - Exercise 1.1 [पृष्ठ १२]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 1 Differentiation
Exercise 1.1 | Q 2.02 | पृष्ठ १२

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