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Differentiate the following w.r.t. x : cos-1(3cosx-sinx2) - Mathematics and Statistics

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प्रश्न

Differentiate the following w.r.t. x : `cos^-1((sqrt(3)cosx - sinx)/(2))`

योग
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उत्तर

Let y = `cos^-1((sqrt(3)cosx - sinx)/(2))`

= `cos^-1[(cosx)((sqrt3)/2) - (sinx)(1/2)]`

= `cos^-1(cosx cos  pi/6 - sinx sin  pi/6)    ...[∵ cos  pi/6 = sqrt(3)/2, sin  pi/6 = (1)/(2)]`

= `cos^-1[cos(x + pi/6)]`

= `x + pi/(6)`
Differentiating w.r.t. x, we get
`"dy"/"dx" = "d"/"dx"(x + pi/6)`

= `"d"/"dx"(x) + "d"/"dx"(pi/6)`
= 1 + 0
= 1.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1: Differentiation - Exercise 1.2 [पृष्ठ ३०]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 1 Differentiation
Exercise 1.2 | Q 8.2 | पृष्ठ ३०

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