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प्रश्न
Differentiate the following w.r.t. x : tan–1(log x)
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उत्तर
Let y = tan–1(log x)
Differentiating w.r.t. x, we get
`"dy"/"dx" = "d"/"dx"[tan^-1 (logx)]`
= `(1)/(1 + (logx)^2)."d"/"dx"(logx)`
= `(1)/(1 + (logx)^2) xx (1)/x`
= `(1)/(x[1 + (logx)^2]`.
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