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Differentiate the following w.r.t.x: sin2x2 – cos2x2

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प्रश्न

Differentiate the following w.r.t.x:

sin2x2 – cos2x2 

योग
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उत्तर

Let y = sin2x2 – cos2x2 
Differentiating w.r.t. x, we get
`"dy"/"dx" = "d"/"dx"[sin^2x^2 - cos^2x^2]`

= `"d"/"dx"(sinx^2)^2 - "d"/"dx"(cosx^2)^2`

= `2sinx^2."d"/"dx"(sinx^2) - 2cosx^2."d"/"dx"(cosx^2)`

= `2sinx^2.cosx^2."d"/"dx"(x^2) - 2cosx^2.(-sinx^2)."d"/"dx"(x^2)`

= 2sin x2 . cos x2 x 2x + 2sinx2 . cosx2 x 2x
= 4x (2sinx2 . cosx2)
= 4x sin(2x2).

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1: Differentiation - Exercise 1.1 [पृष्ठ १२]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 1 Differentiation
Exercise 1.1 | Q 2.18 | पृष्ठ १२

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