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Differentiate the following w.r.t. x: (sin xx)

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प्रश्न

Differentiate the following w.r.t. x: (sin xx)

योग
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उत्तर

Let y = (sin xx)

Then `"dy"/"dx" = "d"/"dx"[(sinx^x)]`

∴ `"dy"/"dx" = cos(x^x)."d"/"dx"(x^x)`          ...(1)
Let u  = xx

Then log u = logxx = x.logx

Differentiating both sides w.r.t. x, we get

`1/u."du"/"dx" = "d"/"dx"(x.logx)`

= `x."d"/"dx"(logx) + (logx)."d"/"dx"(x)`

= `x xx (1)/x + (logx) xx 1`

∴ `"du"/"dx" = u(1 + logx)`

∴ `"d"/"dx"(x^x) = x^x (1 + logx)`             ...(2)

From (1) and (2), we get

`"dy"/"dx" = cos(x^x).x^x(1 + logx)`

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अध्याय 1: Differentiation - Exercise 1.3 [पृष्ठ ३९]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 1 Differentiation
Exercise 1.3 | Q 1.8 | पृष्ठ ३९

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