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Differentiate the following w.r.t. x : cot-1(sin3x1+cos3x)

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प्रश्न

Differentiate the following w.r.t. x : `cot^-1((sin3x)/(1 + cos3x))`

योग
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उत्तर

Let y = `cot^-1((sin3x)/(1 + cos3x))`

= `cot^-1[(2sin((3x)/2)cos((3x)/2))/(2cos^2((3x)/2))]`

= `cot^-1[tan((3x)/2)]`

= `cot^-1[cot(pi/2 - (3x)/2)]`

= `pi/(2) - (3x)/(2)`
Differentiating w.r.t. x, we get
`"dy"/"dx" = "d"/"dx"(pi/2 - (3x)/2)`

= `"d"/"dx"(pi/2) - (3)/(2)"dx"/"dx"`

= `0 - (3)/(2) xx 1`

= `-(3)/(2)`.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1: Differentiation - Exercise 1.2 [पृष्ठ २९]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 1 Differentiation
Exercise 1.2 | Q 7.08 | पृष्ठ २९

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