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Differentiate the following w.r.t.x: ex+1ex-1 - Mathematics and Statistics

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प्रश्न

Differentiate the following w.r.t.x: `(e^sqrt(x) + 1)/(e^sqrt(x) - 1)`

योग
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उत्तर

Let y = `(e^sqrt(x) + 1)/(e^sqrt(x) - 1)`
Differentiating w.r.t. x, we get

`"dy"/"dx" = "d"/"dx"((e^sqrt(x) + 1)/(e^sqrt(x) - 1))`

= `((e^sqrt(x) - 1)"d"/"dx"(e^sqrt(x) + 1) - (e^sqrt(x) + 1)"d"/"dx"(e^sqrt(x) - 1))/(e^sqrt(x) - 1)^2`

= `((e^sqrt(x) - 1)[e^sqrt(x)."d"/"dx"(sqrt(x)) + 0] - (e^sqrt(x) + 1)[e^sqrt(x)."d"/"dx"(sqrt(x)) - 0])/(e^sqrt(x) - 1)^2`

= `((e^sqrt(x) - 1)[e^sqrt(x) xx 1/(2sqrt(x))] - (e^sqrt(x) + 1)[e^sqrt(x) xx 1/(2sqrt(x))])/(e^sqrt(x) - 1)^2`

= `((e^sqrt(x))/(2sqrt(x))(e^sqrt(x) - 1 - e^sqrt(x) - 1))/(e^sqrt(x) - 1)^2`

= `(-e^sqrt(x))/(sqrt(x)(e^sqrt(x) - 1)^2`.

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अध्याय 1: Differentiation - Exercise 1.1 [पृष्ठ १२]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 1 Differentiation
Exercise 1.1 | Q 3.11 | पृष्ठ १२

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