मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Differentiate the following w.r.t.x: ex+1ex-1

Advertisements
Advertisements

प्रश्न

Differentiate the following w.r.t.x: `(e^sqrt(x) + 1)/(e^sqrt(x) - 1)`

बेरीज
Advertisements

उत्तर

Let y = `(e^sqrt(x) + 1)/(e^sqrt(x) - 1)`
Differentiating w.r.t. x, we get

`"dy"/"dx" = "d"/"dx"((e^sqrt(x) + 1)/(e^sqrt(x) - 1))`

= `((e^sqrt(x) - 1)"d"/"dx"(e^sqrt(x) + 1) - (e^sqrt(x) + 1)"d"/"dx"(e^sqrt(x) - 1))/(e^sqrt(x) - 1)^2`

= `((e^sqrt(x) - 1)[e^sqrt(x)."d"/"dx"(sqrt(x)) + 0] - (e^sqrt(x) + 1)[e^sqrt(x)."d"/"dx"(sqrt(x)) - 0])/(e^sqrt(x) - 1)^2`

= `((e^sqrt(x) - 1)[e^sqrt(x) xx 1/(2sqrt(x))] - (e^sqrt(x) + 1)[e^sqrt(x) xx 1/(2sqrt(x))])/(e^sqrt(x) - 1)^2`

= `((e^sqrt(x))/(2sqrt(x))(e^sqrt(x) - 1 - e^sqrt(x) - 1))/(e^sqrt(x) - 1)^2`

= `(-e^sqrt(x))/(sqrt(x)(e^sqrt(x) - 1)^2`.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 1: Differentiation - Exercise 1.1 [पृष्ठ १२]

APPEARS IN

संबंधित प्रश्‍न

Differentiate the following w.r.t.x:

`(sqrt(3x - 5) - 1/sqrt(3x - 5))^5`


Differentiate the following w.r.t.x: cos(x2 + a2)


Differentiate the following w.r.t.x:

`sqrt(e^((3x + 2) +  5)`


Differentiate the following w.r.t.x: `log[tan(x/2)]`


Differentiate the following w.r.t.x: cot3[log(x3)]


Differentiate the following w.r.t.x:

tan[cos(sinx)]


Differentiate the following w.r.t.x: [log {log(logx)}]2


Differentiate the following w.r.t.x:

sin2x2 – cos2x2 


Differentiate the following w.r.t.x: `cot(logx/2) - log(cotx/2)`


Differentiate the following w.r.t.x:

`(e^(2x) - e^(-2x))/(e^(2x) + e^(-2x))`


Differentiate the following w.r.t.x:

`log(sqrt((1 - cos3x)/(1 + cos3x)))`


Differentiate the following w.r.t.x:

`log(sqrt((1 + cos((5x)/2))/(1 - cos((5x)/2))))`


Differentiate the following w.r.t.x:

`log[a^(cosx)/((x^2 - 3)^3 logx)]`


Differentiate the following w.r.t. x : `tan^-1(sqrt(x))`


Differentiate the following w.r.t. x : `sin^-1(x^(3/2))`


Differentiate the following w.r.t. x : `cot^-1[cot(e^(x^2))]`


Differentiate the following w.r.t. x : `"cosec"^-1[1/cos(5^x)]`


Differentiate the following w.r.t. x :

`cos^-1(sqrt(1 - cos(x^2))/2)`


Differentiate the following w.r.t. x :

`cos^-1((1 - x^2)/(1 + x^2))`


Differentiate the following w.r.t. x : `tan^-1((2x)/(1 - x^2))`


Differentiate the following w.r.t. x :

`cos^-1  ((1 - 9^x))/((1 + 9^x)`


Differentiate the following w.r.t. x:

`sin^-1  ((1 - 25x^2)/(1 + 25x^2))`


Differentiate the following w.r.t. x : `cot^-1((1 - sqrt(x))/(1 + sqrt(x)))`


Differentiate the following w.r.t. x : `tan^-1((2sqrt(x))/(1 + 3x))`


Differentiate the following w.r.t. x :

`tan^(−1)[(2^(x + 2))/(1 − 3(4^x))]`


Differentiate the following w.r.t. x : `cot^-1((4 - x - 2x^2)/(3x + 2))`


Differentiate the following w.r.t. x : `(x^5.tan^3 4x)/(sin^2 3x)`


Differentiate the following w.r.t. x: `x^(tan^(-1)x`


Differentiate the following w.r.t. x: (sin xx)


Differentiate the following w.r.t. x :

etanx + (logx)tanx 


Differentiate the following w.r.t. x : `[(tanx)^(tanx)]^(tanx) "at"  x = pi/(4)`


Show that `"dy"/"dx" = y/x` in the following, where a and p are constants : x7.y5 = (x + y)12 


Show that `"dy"/"dx" = y/x` in the following, where a and p are constants : `sec((x^5 + y^5)/(x^5 - y^5))` = a2 


Show that `"dy"/"dx" = y/x` in the following, where a and p are constants : `cos^-1((7x^4 + 5y^4)/(7x^4 - 5y^4)) = tan^-1a`


If y = sin−1 (2x), find `("d"y)/(""d"x)` 


If f(x) is odd and differentiable, then f′(x) is


Differentiate sin2 (sin−1(x2)) w.r. to x


Differentiate `sin^-1((2cosx + 3sinx)/sqrt(13))` w.r. to x


Derivative of (tanx)4 is ______ 


A particle moves so that x = 2 + 27t - t3. The direction of motion reverses after moving a distance of ______ units.


If f(x) = `(3x + 1)/(5x - 4)` and t = `(5 + 3x)/(x - 4)`, then f(t) is ______ 


Let f(x) = `(1 - tan x)/(4x - pi), x ne pi/4, x ∈ [0, pi/2]`. If f(x) is continuous in `[0, pi/2]`, then f`(pi/4)` is ______.


If y = cosec x0, then `"dy"/"dx"` = ______.


If x = p sin θ, y = q cos θ, then `dy/dx` = ______ 


Solve `x + y (dy)/(dx) = sec(x^2 + y^2)`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×