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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Differentiate the following w.r.t.x: 5sin3x+3

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प्रश्न

Differentiate the following w.r.t.x: `5^(sin^3x + 3)`

बेरीज
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उत्तर

Let y = `5^(sin^3x + 3)`

Differentiating w.r.t. x,we get,

`"dy"/"dx" = "d"/"dx"(5^(sin^3x + 3))`

= `5^(sin^3x + 3)·log5·"d"/"dx"(sin^3x + 3)`

= `5^(sin^3x + 3)·log5·[3sin^2x·"d"/"dx"(sin x) + 0]`

= `5^(sin^3x + 3)·log5·[3sin^2x cosx]`

= `3sin^2x cosx·5^(sin^3x + 3)·log5`.

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पाठ 1: Differentiation - Exercise 1.1 [पृष्ठ १२]

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