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प्रश्न
Differentiate the following w.r.t. x : `sin^4[sin^-1(sqrt(x))]`
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उत्तर
Let y = `sin^4[sin^-1(sqrt(x))]`
= `{sin[sin^-1(sqrt(x))]}^4`
= `(sqrt(x))^4`
= x2
Differentiating w.r.t. x, we get
`"dy"/"dx"= "d"/"dx"(x^2)`
= 2x.
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