मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Differentiate the following w.r.t.x: e3sin2x-2cos2x

Advertisements
Advertisements

प्रश्न

Differentiate the following w.r.t.x: `e^(3sin^2x - 2cos^2x)`

बेरीज
Advertisements

उत्तर

Let y = `e^(3sin^2x - 2cos^2x)`
Differentiating w.r.t. x, we get
`"dy"/"dx" = "d"/"dx"[e^(3sin^2x - 2cos^2x)]`

= `e^(3sin^2x - 2cos^2x)."d"/"dx"(3sin^2x - 2cos^2x)`

= `e^(3sin^2x - 2cos^2x).[3"d"/"dx"(sinx)^2 - 2"d"/"dx"(cos^2x)]`

= `e^(3sin^2x - 2cos^2x).[3 xx 2sinx. "d"/"dx"(sinx) - 2 xx 2cosx."d"/"dx"(cosx)]`

= `e^(3sin^2x - 2cos^2x).[6sinx cosx - 4cosx (-sinx)]`

= `e^(3sin^2x - 2cos^2x).(10sinx cosx)`

= `5(2sinx cosx).e^(3sin^2x - 2cos^2x)`

= `5sin2x.e^(3sin^2x - 2cos^2x)`.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 1: Differentiation - Exercise 1.1 [पृष्ठ १२]

APPEARS IN

संबंधित प्रश्‍न

Differentiate the following w.r.t. x:

(x3 – 2x – 1)5


Differentiate the following w.r.t.x:

`(2x^(3/2) - 3x^(4/3) - 5)^(5/2)`


Differentiate the following w.r.t.x: `(8)/(3root(3)((2x^2 - 7x - 5)^11`


Differentiate the following w.r.t.x:

`(sqrt(3x - 5) - 1/sqrt(3x - 5))^5`


Differentiate the following w.r.t.x: cos(x2 + a2)


Differentiate the following w.r.t.x:

`sqrt(e^((3x + 2) +  5)`


Differentiate the following w.r.t.x: `sqrt(tansqrt(x)`


Differentiate the following w.r.t.x: `5^(sin^3x + 3)`


Differentiate the following w.r.t.x: `log_(e^2) (log x)`


Differentiate the following w.r.t.x: (1 + 4x)5 (3 + x −x2)


Differentiate the following w.r.t.x: `cot(logx/2) - log(cotx/2)`


Differentiate the following w.r.t.x:

`(e^(2x) - e^(-2x))/(e^(2x) + e^(-2x))`


Differentiate the following w.r.t.x: `log[4^(2x)((x^2 + 5)/(sqrt(2x^3 - 4)))^(3/2)]`


Differentiate the following w.r.t.x:

`log[a^(cosx)/((x^2 - 3)^3 logx)]`


Differentiate the following w.r.t. x : cot–1(x3)


Differentiate the following w.r.t. x :

cos3[cos–1(x3)]


Differentiate the following w.r.t. x : `tan^-1[(1 - tan(x/2))/(1 + tan(x/2))]`


Differentiate the following w.r.t. x : `tan^-1[(1 + cos(x/3))/(sin(x/3))]`


Differentiate the following w.r.t. x : `tan^-1(sqrt((1 + cosx)/(1 - cosx)))`


Differentiate the following w.r.t. x : `sin^-1((4sinx + 5cosx)/sqrt(41))`


Differentiate the following w.r.t. x : `cos^-1((sqrt(3)cosx - sinx)/(2))`


Differentiate the following w.r.t. x : `sin^-1((cossqrt(x) + sinsqrt(x))/sqrt(2))`


Differentiate the following w.r.t. x : `tan^-1((2x)/(1 - x^2))`


Differentiate the following w.r.t. x :

`cos^-1  ((1 - 9^x))/((1 + 9^x)`


Differentiate the following w.r.t. x:

`tan^-1((2x^(5/2))/(1 - x^5))`


Differentiate the following w.r.t. x : `tan^-1((2sqrt(x))/(1 + 3x))`


Differentiate the following w.r.t. x : `cot^-1((4 - x - 2x^2)/(3x + 2))`


Differentiate the following w.r.t. x :

`(x +  1)^2/((x + 2)^3(x + 3)^4`


Differentiate the following w.r.t. x: (sin xx)


Differentiate the following w.r.t. x : `x^(e^x) + (logx)^(sinx)`


Show that `"dy"/"dx" = y/x` in the following, where a and p are constants : x7.y5 = (x + y)12 


Show that `"dy"/"dx" = y/x` in the following, where a and p are constants : `tan^-1((3x^2 - 4y^2)/(3x^2 + 4y^2))` = a2 


Show that `"dy"/"dx" = y/x` in the following, where a and p are constants : `sin((x^3 - y^3)/(x^3 + y^3))` = a3 


Differentiate y = etanx w.r. to x


If y = `tan^-1[sqrt((1 + cos x)/(1 - cos x))]`, find `("d"y)/("d"x)`


Differentiate `tan^-1((8x)/(1 - 15x^2))` w.r. to x


If y = `sin^-1[("a"cosx - "b"sinx)/sqrt("a"^2 + "b"^2)]`, then find `("d"y)/("d"x)`


If f(x) = 3x - 2 and g(x) = x2, then (fog)(x) = ________.


If x = `sqrt("a"^(sin^-1 "t")), "y" = sqrt("a"^(cos^-1 "t")), "then" "dy"/"dx"` = ______


Derivative of (tanx)4 is ______ 


y = {x(x - 3)}2 increases for all values of x lying in the interval.


Let f(x) = `(1 - tan x)/(4x - pi), x ne pi/4, x ∈ [0, pi/2]`. If f(x) is continuous in `[0, pi/2]`, then f`(pi/4)` is ______.


Let f(x) be a polynomial function of the second degree. If f(1) = f(–1) and a1, a2, a3 are in AP, then f’(a1), f’(a2), f’(a3) are in ______.


If `cos((x^2 - y^2)/(x^2 + y^2))` = log a, show that `dy/dx = y/x`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×