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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Differentiate the following w.r.t. x: (x3 – 2x – 1)5

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प्रश्न

Differentiate the following w.r.t. x:

(x3 – 2x – 1)5

बेरीज
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उत्तर

To differentiate the function

y = (x3 − 2x − 1)5

u = x3 − 2x − 1 

Then y = u5

By the chain rule:

`dy/dx = dy/(du) . (du)/dx`

`dy/(du) = 5u^4`

`(du)/dx = d/dx (x^3 - 2x - 1) = 3x^2 - 2`

`dy/dx = 5(x^3 - 2x-1)^4 . (3x^2 - 2)`

`d/dx [(x^3-2x-1^5)] = 5(x^3 - 2x - 1)^4 (3x^2-2)`

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पाठ 1: Differentiation - Exercise 1.1 [पृष्ठ ११]

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