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प्रश्न
Differentiate the following w.r.t. x:
(x3 – 2x – 1)5
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उत्तर
To differentiate the function
y = (x3 − 2x − 1)5
u = x3 − 2x − 1
Then y = u5
By the chain rule:
`dy/dx = dy/(du) . (du)/dx`
`dy/(du) = 5u^4`
`(du)/dx = d/dx (x^3 - 2x - 1) = 3x^2 - 2`
`dy/dx = 5(x^3 - 2x-1)^4 . (3x^2 - 2)`
`d/dx [(x^3-2x-1^5)] = 5(x^3 - 2x - 1)^4 (3x^2-2)`
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