हिंदी

Differentiate the following w.r.t.x: cot3[log(x3)]

Advertisements
Advertisements

प्रश्न

Differentiate the following w.r.t.x: cot3[log(x3)]

योग
Advertisements

उत्तर

Let y = cot3[log(x3)]

Differentiating w.r.t. x,we get,

`"dy"/"dx" = "d"/"dx"[cot(logx^3)]^3`

∴ `"dy"/"dx" = 3[cot(logx^3)]^2*"d"/"dx"[cot(logx^3)]`

∴ `"dy"/"dx" = 3cot^2[log(x^3)]*[-"cosec"^2(logx^3)]*"d"/"dx"(logx^3)`

∴ `"dy"/"dx" = -3cot^2[log(x^3)]*"cosec"^2[log(x^3)]*3"d"/"dx"(logx)`

∴ `"dy"/"dx" = -3cot^2[log(x^3)]*"cosec"^2[log(x^3)] * 3 xx 1/x`

∴ `"dy"/"dx" = (-9" cosec"^2[log(x^3)]*cot^2[log(x^3)]]/x`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1: Differentiation - Exercise 1.1 [पृष्ठ १२]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 1 Differentiation
Exercise 1.1 | Q 2.05 | पृष्ठ १२

संबंधित प्रश्न

Differentiate the following w.r.t.x:

`(sqrt(3x - 5) - 1/sqrt(3x - 5))^5`


Differentiate the following w.r.t.x: `sqrt(tansqrt(x)`


Differentiate the following w.r.t.x: `5^(sin^3x + 3)`


Differentiate the following w.r.t.x: `"cosec"(sqrt(cos x))`


Differentiate the following w.r.t.x: `e^(3sin^2x - 2cos^2x)`


Differentiate the following w.r.t.x: `e^(log[(logx)^2 - logx^2]`


Differentiate the following w.r.t.x: `sinsqrt(sinsqrt(x)`


Differentiate the following w.r.t.x: `log[sec (e^(x^2))]`


Differentiate the following w.r.t.x: `log_(e^2) (log x)`


Differentiate the following w.r.t.x:

(x2 + 4x + 1)3 + (x3− 5x − 2)4 


Differentiate the following w.r.t.x:

`(x^3 - 5)^5/(x^3 + 3)^3`


Differentiate the following w.r.t.x:

`(e^(2x) - e^(-2x))/(e^(2x) + e^(-2x))`


Differentiate the following w.r.t.x: `log[(ex^2(5 - 4x)^(3/2))/root(3)(7 - 6x)]`


Differentiate the following w.r.t. x: 

`sin^-1(sqrt((1 + x^2)/2))`


Differentiate the following w.r.t. x : `sin^-1(x^(3/2))`


Differentiate the following w.r.t. x : `cot^-1[cot(e^(x^2))]`


Differentiate the following w.r.t. x : `"cosec"^-1[1/cos(5^x)]`


Differentiate the following w.r.t. x : `cot^-1((sin3x)/(1 + cos3x))`


Differentiate the following w.r.t. x : `tan^-1((cos7x)/(1 + sin7x))`


Differentiate the following w.r.t. x : `tan^-1(sqrt((1 + cosx)/(1 - cosx)))`


Differentiate the following w.r.t.x:

tan–1 (cosec x + cot x)


Differentiate the following w.r.t. x : `sin^-1((cossqrt(x) + sinsqrt(x))/sqrt(2))`


Differentiate the following w.r.t. x : `cos^-1((3cos3x - 4sin3x)/5)`


Differentiate the following w.r.t. x :

`cos^-1[(3cos(e^x) + 2sin(e^x))/sqrt(13)]`


Differentiate the following w.r.t. x : `sin^-1((1 - x^2)/(1 + x^2))`


Differentiate the following w.r.t. x : cos–1(3x – 4x3)


Differentiate the following w.r.t. x : `tan^-1((8x)/(1 - 15x^2))`


Differentiate the following w.r.t. x : `tan^-1((2^x)/(1 + 2^(2x + 1)))`


Differentiate the following w.r.t. x : `tan^-1((a + btanx)/(b - atanx))`


Differentiate the following w.r.t. x :

`(x +  1)^2/((x + 2)^3(x + 3)^4`


Differentiate the following w.r.t. x : `(x^5.tan^3 4x)/(sin^2 3x)`


Differentiate the following w.r.t. x: `x^(tan^(-1)x`


Differentiate the following w.r.t. x :

etanx + (logx)tanx 


Differentiate the following w.r.t. x : `[(tanx)^(tanx)]^(tanx) "at"  x = pi/(4)`


Show that `"dy"/"dx" = y/x` in the following, where a and p are constants : `sin((x^3 - y^3)/(x^3 + y^3))` = a3 


If f(x) is odd and differentiable, then f′(x) is


If y = `"e"^(1 + logx)` then find `("d"y)/("d"x)` 


Differentiate `tan^-1((8x)/(1 - 15x^2))` w.r. to x


If x = `sqrt("a"^(sin^-1 "t")), "y" = sqrt("a"^(cos^-1 "t")), "then" "dy"/"dx"` = ______


If `t = v^2/3`, then `(-v/2 (df)/dt)` is equal to, (where f is acceleration) ______ 


The weight W of a certain stock of fish is given by W = nw, where n is the size of stock and w is the average weight of a fish. If n and w change with time t as n = 2t2 + 3 and w = t2 - t + 2, then the rate of change of W with respect to t at t = 1 is ______ 


If f(x) = `(3x + 1)/(5x - 4)` and t = `(5 + 3x)/(x - 4)`, then f(t) is ______ 


The differential equation of the family of curves y = `"ae"^(2(x + "b"))` is ______.


Let f(x) = `(1 - tan x)/(4x - pi), x ne pi/4, x ∈ [0, pi/2]`. If f(x) is continuous in `[0, pi/2]`, then f`(pi/4)` is ______.


The volume of a spherical balloon is increasing at the rate of 10 cubic centimetre per minute. The rate of change of the surface of the balloon at the instant when its radius is 4 centimetres, is ______


Differentiate `tan^-1 (sqrt((3 - x)/(3 + x)))` w.r.t. x.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×