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प्रश्न
Differentiate the following w.r.t. x : `cot^-1[cot(e^(x^2))]`
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उत्तर
Let y = `cot^-1[cot(e^(x^2))] = e^(x^2)`
Differentiating w.r.t. x, we get
`"dy"/"dx" = "d"/"dx"(e^(x^2))`
= `e^(x^2).("d"(x^2))/"dx"`
= `e^(x^2). 2x`
= `2x.e^(x^2)`.
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