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Differentiate the following w.r.t. x : coseccosec-1[1cos(5x)]

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प्रश्न

Differentiate the following w.r.t. x : `"cosec"^-1[1/cos(5^x)]`

योग
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उत्तर

Let y = `"cosec"^-1[1/cos(5^x)]`
= cosec–1[sec(5x)]

= `"cosec"^-1["cosec"(pi/2 - 5^x)]`

= `pi/(2) - 5^x`
Differentiating w.r.t. x, we get
`"dy"/"dx" = "d"/"dx"(pi/2 - 5^x)`

= `"d"/"dx"(pi/2) - "d"/"dx"(5^x)`
= 0 –5x.log5
= –5x.log5.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1: Differentiation - Exercise 1.2 [पृष्ठ २९]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 1 Differentiation
Exercise 1.2 | Q 7.02 | पृष्ठ २९

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