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Differentiate the following w.r.t. x : coseccosec-1(14cos32x-3cos2x)

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प्रश्न

Differentiate the following w.r.t. x : `"cosec"^-1((1)/(4cos^3 2x - 3cos2x))`

योग
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उत्तर

Let y = `"cosec"^-1((1)/(4cos^3 2x - 3cos2x))`

= `"cosec"^-1(1/(cos6x))`   ...[∵ cos3x = 4cos3x – 3cosx]

= cosec–1(sec6x)

= `"cosec"^-1["cosec"(pi/2 - 6x)]`

= `pi/(2) - 6x`
Differentiating w.r.t. x, we get
`"dy"/"dx" = "d"/"dx"(pi/2 - 6x)`

= `"d"/"dx"(pi/2) - 6"d"/"dx"(x)`
= 0 – 6 x 1
= –6.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1: Differentiation - Exercise 1.2 [पृष्ठ २९]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 1 Differentiation
Exercise 1.2 | Q 7.06 | पृष्ठ २९

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