हिंदी

Differentiate the following w.r.t. x : cosec–1 (e–x)

Advertisements
Advertisements

प्रश्न

Differentiate the following w.r.t. x : cosec–1 (e–x)

योग
Advertisements

उत्तर

Let y = cosec–1 (e–x)
Differentiating w.r.t. x, we get
`"dy"/"dx" = "d"/"dx"["cosec"^-1 (e^-x)]`

= `(-1)/(e^-x sqrt((e^-x)^2 - 1))."d"/"dx"(e^-x)`

= `(-1)/(e^-x sqrt(e^(-2x) - 1)) xx e^-x."d"/"dx"(– x)`

= `(-1)/sqrt(e^(-2x) - 1) xx -1`

= `(1)/(sqrt(1/e^(2x) - 1)`

= `e^x/(sqrt(1 - e^(2x))`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1: Differentiation - Exercise 1.2 [पृष्ठ २९]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 1 Differentiation
Exercise 1.2 | Q 6.02 | पृष्ठ २९

संबंधित प्रश्न

Differentiate the following w.r.t.x:

`(2x^(3/2) - 3x^(4/3) - 5)^(5/2)`


Differentiate the following w.r.t. x: `sqrt(x^2 + 4x - 7)`.


Differentiate the following w.r.t.x:

`sqrt(x^2 + sqrt(x^2 + 1)`


Differentiate the following w.r.t.x: `log[tan(x/2)]`


Differentiate the following w.r.t.x: `"cosec"(sqrt(cos x))`


Differentiate the following w.r.t.x:

tan[cos(sinx)]


Differentiate the following w.r.t.x: `e^(log[(logx)^2 - logx^2]`


Differentiate the following w.r.t.x: `log_(e^2) (log x)`


Differentiate the following w.r.t.x: [log {log(logx)}]2


Differentiate the following w.r.t.x:

sin2x2 – cos2x2 


Differentiate the following w.r.t.x: `x/(sqrt(7 - 3x)`


Differentiate the following w.r.t.x:

log (sec 3x+ tan 3x)


Differentiate the following w.r.t.x: `(1 + sinx°)/(1 - sinx°)`


Differentiate the following w.r.t.x:

`log(sqrt((1 - cos3x)/(1 + cos3x)))`


Differentiate the following w.r.t.x:

y = (25)log5(secx) − (16)log4(tanx) 


Differentiate the following w.r.t. x : tan–1(log x)


Differentiate the following w.r.t. x : cot–1(x3)


Differentiate the following w.r.t. x: 

`sin^-1(sqrt((1 + x^2)/2))`


Differentiate the following w.r.t. x : `sin^-1(x^(3/2))`


Differentiate the following w.r.t. x :

cos3[cos–1(x3)]


Differentiate the following w.r.t. x : `"cosec"^-1((1)/(4cos^3 2x - 3cos2x))`


Differentiate the following w.r.t. x :

`cot^-1[(sqrt(1 + sin  ((4x)/3)) + sqrt(1 - sin  ((4x)/3)))/(sqrt(1 + sin  ((4x)/3)) - sqrt(1 - sin  ((4x)/3)))]`


Differentiate the following w.r.t. x :

`cos^-1[(3cos(e^x) + 2sin(e^x))/sqrt(13)]`


Differentiate the following w.r.t. x : `"cosec"^-1[(10)/(6sin(2^x) - 8cos(2^x))]`


Differentiate the following w.r.t. x : `sin^-1((1 - x^2)/(1 + x^2))`


Differentiate the following w.r.t. x : `sin^-1(2xsqrt(1 - x^2))`


Differentiate the following w.r.t. x : cos–1(3x – 4x3)


Differentiate the following w.r.t. x:

`sin^-1  ((1 - 25x^2)/(1 + 25x^2))`


Differentiate the following w.r.t. x : `cot^-1((1 - sqrt(x))/(1 + sqrt(x)))`


Differentiate the following w.r.t.x:

`cot^-1((1 + 35x^2)/(2x))`


Differentiate the following w.r.t. x :

`tan^(−1)[(2^(x + 2))/(1 − 3(4^x))]`


Differentiate the following w.r.t. x : `tan^-1((2^x)/(1 + 2^(2x + 1)))`


Show that `"dy"/"dx" = y/x` in the following, where a and p are constants : x7.y5 = (x + y)12 


Show that `"dy"/"dx" = y/x` in the following, where a and p are constants : `cos^-1((7x^4 + 5y^4)/(7x^4 - 5y^4)) = tan^-1a`


If y = `"e"^(1 + logx)` then find `("d"y)/("d"x)` 


If y = `tan^-1[sqrt((1 + cos x)/(1 - cos x))]`, find `("d"y)/("d"x)`


If y = `sin^-1[("a"cosx - "b"sinx)/sqrt("a"^2 + "b"^2)]`, then find `("d"y)/("d"x)`


Derivative of (tanx)4 is ______ 


y = {x(x - 3)}2 increases for all values of x lying in the interval.


A particle moves so that x = 2 + 27t - t3. The direction of motion reverses after moving a distance of ______ units.


If y = `(3x^2 - 4x + 7.5)^4, "then"  dy/dx` is ______ 


The differential equation of the family of curves y = `"ae"^(2(x + "b"))` is ______.


Find `(dy)/(dx)`, if x3 + x2y + xy2 + y3 = 81


The value of `d/(dx)[tan^-1((a - x)/(1 + ax))]` is ______.


Diffierentiate: `tan^-1((a + b cos x)/(b - a cos x))` w.r.t.x.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×