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प्रश्न
If y = `"e"^(1 + logx)` then find `("d"y)/("d"x)`
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उत्तर
y = `"e"^(1 + logx)`
= `"e"*"e"^(logx)`
= e. x
∴ `("d"y)/("d"x)` = e. 1 = e
OR
y = `"e"^(1 + logx)`
`("d"y)/("d"x) = "d"/("d"x)("e"^(1 + logx))`
= `"e"^(1 + logx) * "d"/("d"x)(1 + log x)`
= `"e"^(1 + logx) * (0 + 1/x)`
= `("e"^(1 + log x))/x`
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