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Differentiate the following w.r.t.x: elog[(logx)2-logx2]

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प्रश्न

Differentiate the following w.r.t.x: `e^(log[(logx)^2 - logx^2]`

योग
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उत्तर

Let y = `e^(log[(logx)^2 − logx^2]`

∴ y = (logx)2 – log x2             ...[∵ elog x = x]

Differentiating w.r.t. x, we get

`"dy"/"dx" = "d"/"dx"[(log x)^2 − logx^2]`

∴ `"dy"/"dx" = "d"/"dx"(log x)^2 − "d"/"dx"(log x^2)`

∴ `"dy"/"dx" = 2 log x. "d"/"dx"(log x) − 1/x^2. "d"/"dx" x^2`

∴ `"dy"/"dx" = 2 log x. 1/x − 1/x^2. 2x`

∴ `"dy"/"dx" = (2log x)/x − 2/x`

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अध्याय 1: Differentiation - Exercise 1.1 [पृष्ठ १२]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 1 Differentiation
Exercise 1.1 | Q 2.13 | पृष्ठ १२

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