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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Differentiate the following w.r.t.x: sec[tan (x4 + 4)]

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प्रश्न

Differentiate the following w.r.t.x: sec[tan (x4 + 4)]

बेरीज
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उत्तर

Let y = sec[tan (x4 + 4)]
Differentiating w.r.t. x, we get
`"dy"/"dx" = "d"/"dx"{sec[tan(x^4 + 4)]}`

= `sec[tan(x^4 + 4)].tan[tan(x^4 + 4)]."d"/"dx"[tan(x^4 + 4)]`

= `sec[tan(x^4 + 4)].tan[tan(x^4 + 4)].sec^2(x^4 + 4)."d"/"dx"(x^4 + 4)`

= sec[tan(x4 + 4)]·tan[tan(x4 + 4)]·sec2(x4 + 4).(4x3 + 0)
= 4x3·sec2(x4 + 4)·sec[tan(x4 + 4)]·tan[tan(x4 + 4)].

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पाठ 1: Differentiation - Exercise 1.1 [पृष्ठ १२]

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