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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Differentiate cot-1(cosx1+sinx) w.r. to x

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प्रश्न

Differentiate `cot^-1((cos x)/(1 + sinx))` w.r. to x

बेरीज
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उत्तर

Let y = `cot^-1((cos x)/(1 + sinx))`

= `tan^-1((1 + sinx)/(cos x))`

= `tan^-1[(cos^2(x/2) + sin^2(x/2) + 2sin(x/2)cos(x/2))/(cos^2(x/2) - sin^2(x/2))]`

= `tan^-1[{cos(x/2) + sin(x/2)}^2/([cos(x/2) + sin(x/2)][cos(x/2) - sin(x/2)])]`

= `tan^-1[(cos(x/2) + sin(x/2))/(cos(x/2) - sin(x/2))]`

= `tan^-1[(1 + tan(x/2))/(1 - tan(x/2))]`

= `tan^-1[(tan(pi/4) + tan(pi/2))/(1 - tan(pi/4)tan(x/2))]`

= `tan^-1[tan(pi/4 + x/2)]`

∴ y = `pi/4 + x/2`

Differentiating w. r. t. x, we get

`("d"y)/("d"x) = "d"/("d"x)(pi/4 + x/2) = 0 + 1/2 = 1/2`

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पाठ 2.1: Differentiation - Short Answers II

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