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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Differentiate the following w.r.t.x: cot-1(1+35x22x)

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प्रश्न

Differentiate the following w.r.t.x:

`cot^-1((1 + 35x^2)/(2x))`

बेरीज
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उत्तर

Let y = `cot^-1((1 + 35x^2)/(2x))`

= `tan^-1((2x)/(1 + 35x^2))   ...[∵ cot^-1 x = tan^-1(1/x)]`

= `tan^-1[(7x - 5x)/(1 + (7x)(5x))]`

= tan–1(7x) – tan–1(5x)

Differentiating w.r.t.x, we get

`(dy)/dx = d/dx [tan^-1 (7x) - tan^-1(5x)]`

= `d/dx [tan^-1(7x)] - d/dx [tan^-1(5x)]`

= `1/(1 + (7x)^2) * d/dx (7x) - 1/(1 + (5x)^2) * d/dx (5x)`

= `1/(1 + 49x^2) xx 7 - 1/(1 + 25x^2) xx 5`

= `7/(1 + 49x^2) - 5/(1 + 25x^2)`

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पाठ 1: Differentiation - Exercise 1.2 [पृष्ठ ३०]

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