मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Differentiate the following w.r.t. x : sin-1(cosx+sinx2) - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Differentiate the following w.r.t. x : `sin^-1((cossqrt(x) + sinsqrt(x))/sqrt(2))`

बेरीज
Advertisements

उत्तर

y = `sin^-1((cossqrt(x) + sinsqrt(x))/sqrt(2))`

= `sin^-1(1/sqrt(2)cossqrt(x) + 1/sqrt(2)sinsqrt(x))`
Put,
`(1)/sqrt(2)` = sinx

`(1)/sqrt(2)` = cosα
Also,
sin2α + cos2α = `(1/sqrt(2))^2 + (1/sqrt(2))^2` = 1
And,
tanα = 1
∴ α = tan–11
y = `sin^(–1)(sinα.cossqrt(x) + cosα.sin(x)`
= `sin^(-1)(sin(α + sqrt(x)))`
y = `α + sqrt(x)`
y = `tan^-1(1) + sqrt(x)`
Differentiating w.r.t. x, we get
`"dy"/"dx" = "d"/"dx"(tan^-1 + sqrt(x))`

= `0 + 1/(2sqrt(x))`

= `(1)/(2sqrt(x))`.

shaalaa.com
Differentiation
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 1: Differentiation - Exercise 1.2 [पृष्ठ ३०]

APPEARS IN

संबंधित प्रश्‍न

Differentiate the following w.r.t.x:

`(2x^(3/2) - 3x^(4/3) - 5)^(5/2)`


Differentiate the following w.r.t. x: `sqrt(x^2 + 4x - 7)`.


Differentiate the following w.r.t.x:

`(sqrt(3x - 5) - 1/sqrt(3x - 5))^5`


Differentiate the following w.r.t.x: sec[tan (x4 + 4)]


Differentiate the following w.r.t.x: `log_(e^2) (log x)`


Differentiate the following w.r.t.x: [log {log(logx)}]2


Differentiate the following w.r.t.x:

(x2 + 4x + 1)3 + (x3− 5x − 2)4 


Differentiate the following w.r.t.x: `x/(sqrt(7 - 3x)`


Differentiate the following w.r.t.x:

log (sec 3x+ tan 3x)


Differentiate the following w.r.t.x:

`log(sqrt((1 - cos3x)/(1 + cos3x)))`


Differentiate the following w.r.t.x:

`log(sqrt((1 + cos((5x)/2))/(1 - cos((5x)/2))))`


Differentiate the following w.r.t.x: `log(sqrt((1 - sinx)/(1 + sinx)))`


Differentiate the following w.r.t.x: `log[4^(2x)((x^2 + 5)/(sqrt(2x^3 - 4)))^(3/2)]`


Differentiate the following w.r.t.x: `log[(ex^2(5 - 4x)^(3/2))/root(3)(7 - 6x)]`


Differentiate the following w.r.t. x : cot–1(x3)


Differentiate the following w.r.t. x : cot–1(4x)


Differentiate the following w.r.t. x : `tan^-1[(1 + cos(x/3))/(sin(x/3))]`


Differentiate the following w.r.t. x : `tan^-1(sqrt((1 + cosx)/(1 - cosx)))`


Differentiate the following w.r.t. x : `tan^-1((2x)/(1 - x^2))`


Differentiate the following w.r.t. x : `sin^-1((1 - x^2)/(1 + x^2))`


Differentiate the following w.r.t. x : cos–1(3x – 4x3)


Differentiate the following w.r.t. x : `cos^-1((e^x -  e^(-x))/(e^x +  e^(-x)))`


Differentiate the following w.r.t. x :

`sin^-1(4^(x + 1/2)/(1 + 2^(4x)))`


Differentiate the following w.r.t. x : `sin^-1  ((1 - 25x^2)/(1 + 25x^2))`


Differentiate the following w.r.t. x :

`sin^(−1) ((1 − x^3)/(1 + x^3))`


Differentiate the following w.r.t. x :

`tan^(−1)[(2^(x + 2))/(1 − 3(4^x))]`


Differentiate the following w.r.t. x: `x^(tan^(-1)x`


Differentiate the following w.r.t. x : (sin x)x 


Differentiate the following w.r.t. x : (logx)x – (cos x)cotx 


Differentiate the following w.r.t. x : `x^(e^x) + (logx)^(sinx)`


Differentiate the following w.r.t. x : `[(tanx)^(tanx)]^(tanx) "at"  x = pi/(4)`


Show that `"dy"/"dx" = y/x` in the following, where a and p are constants : x7.y5 = (x + y)12 


Show that `bb("dy"/"dx" = y/x)` in the following, where a and p are constant:

xpy4 = (x + y)p+4, p ∈ N


Show that `"dy"/"dx" = y/x` in the following, where a and p are constants : `e^((x^7 - y^7)/(x^7 + y^7)` = a


If f(x) is odd and differentiable, then f′(x) is


Differentiate `tan^-1((8x)/(1 - 15x^2))` w.r. to x


If y = `sin^-1[("a"cosx - "b"sinx)/sqrt("a"^2 + "b"^2)]`, then find `("d"y)/("d"x)`


If f(x) = `(3x + 1)/(5x - 4)` and t = `(5 + 3x)/(x - 4)`, then f(t) is ______ 


Find `(dy)/(dx)`, if x3 + x2y + xy2 + y3 = 81


The value of `d/(dx)[tan^-1((a - x)/(1 + ax))]` is ______.


Let f(x) be a polynomial function of the second degree. If f(1) = f(–1) and a1, a2, a3 are in AP, then f’(a1), f’(a2), f’(a3) are in ______.


Differentiate `tan^-1 (sqrt((3 - x)/(3 + x)))` w.r.t. x.


Diffierentiate: `tan^-1((a + b cos x)/(b - a cos x))` w.r.t.x.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×