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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Differentiate y = x2+5 w.r. to x

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प्रश्न

Differentiate y = `sqrt(x^2 + 5)` w.r. to x

बेरीज
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उत्तर

y = `sqrt(x^2 + 5)`

∴ `("d"y)/("d"x) = "d"/("d"x) (sqrt(x^2 + 5))`

= `1/(2sqrt(x^2 + 5)) * "d"/("d"x) (x^2 + 5)`

= `1/(2sqrt(x^2 + 5)) * (2x + 0)`

= `x/sqrt(x^2 + 5)`

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पाठ 2.1: Differentiation - Very Short Answers

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