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प्रश्न
Differentiate the following w.r.t. x : cot–1(4x)
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उत्तर
Let y = cot–1(4x)
Differentiating w.r.t. x, we get
`"dy"/"dx" = "d"/"dx"[cot^-1(4^x)]`
= `(-1)/(1 + (4^x)^2)."d"/"dx"(4^x)`
= `(-1)/(1 + 4^(2x)) xx 4^x log4`
= `(-4^xlog4)/(1 + 4^(2x))`
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