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Differentiate the following w.r.t. x : tan-1(8x1-15x2)

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प्रश्न

Differentiate the following w.r.t. x : `tan^-1((8x)/(1 - 15x^2))`

योग
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उत्तर

Let y = `tan^-1((8x)/(1 - 15x^2))`

= `tan^-1[(5x + 3x)/(1 - (5x)(3x))]`

= tan–1(5x) + tan–1(3x)

Differentiating w.r.t. x, we get

`"dy"/"dx" = "d"/"dx"[tan^-1(5x) + tan^-1(3x)]`

= `"d"/"dx"[tan^-1(5x)] + "d"/"dx"[tan^-1(3x)]`

= `(1)/(1 + (5x)^2)."d"/"dx"(5x) + (1)/(1 + (3x)^2)."d"/"dx"(3x)`

= `(1)/(1 + 25x^2) xx 5 + (1)/(1 + 9x^2) xx 3`

= `(5)/(1 + 25x^2) + (3)/(1 + 9x^2)`

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अध्याय 1: Differentiation - Exercise 1.2 [पृष्ठ ३०]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 1 Differentiation
Exercise 1.2 | Q 10.1 | पृष्ठ ३०

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