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प्रश्न
Construct ☐ BARC such that l(BA) = l(BC) = 4.2 cm, l(AC) = 6.0 cm, l(AR) = l(CR) = 5.6 cm
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उत्तर
Steps of Construction:
Step 1: Draw BA = 4.2 cm.
Step 2: With B as the centre and a radius of 4.2 cm, draw an arc.
Step 3: With A as the centre and a radius of 6 cm, draw an arc cutting the previous arc at C.
Step 4: Join BC.
Step 5: With A as the centre and a radius of 5.6 cm, draw an arc.
Step 6: With C as the centre and a radius of 5.6 cm, draw an arc cutting the previous arc at R.
Step 7: Join AR and CR.
Here, BARC is the required quadrilateral.
संबंधित प्रश्न
Can a quadrilateral ABCD be a parallelogram if ∠A = 70° and ∠C = 65°?
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In parallelogram ABCD, E is the mid-point of side AB and CE bisects angle BCD. Prove that:
- AE = AD,
- DE bisects and ∠ADC and
- Angle DEC is a right angle.
In the following diagram, the bisectors of interior angles of the parallelogram PQRS enclose a quadrilateral ABCD.
Show that:
(i) ∠PSB + ∠SPB = 90°
(ii) ∠PBS = 90°
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(iv) ∠ADC = 90°
(v) ∠A = 90°
(vi) ABCD is a rectangle
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