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Check the injectivity and surjectivity of the following function: f : R → R given by f(x) = x^2

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प्रश्न

Check the injectivity and surjectivity of the following function:

f : R → R given by f(x) = x2

योग
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उत्तर

f : R → R given by f(x) = x2

It is seen that f(–1) = f(1) = 1, but –1 ≠ 1.

∴ f is not injective.

Now, –2 ∈ R, but there does not exist any element x ∈ R such that f(x) = x2 = –2.

∴ f is not surjective.

Hence, function f is neither injective nor surjective.

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अध्याय 1: Relations and Functions - EXERCISE 1.2 [पृष्ठ १०]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 1 Relations and Functions
EXERCISE 1.2 | Q 2. (iii) | पृष्ठ १०

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