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A wire connected to a power supply of 230 V has power dissipation P1. Suppose the wire is cut into two equal pieces and connected parallel to the same power supply.

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प्रश्न

A wire connected to a power supply of 230 V has power dissipation P1. Suppose the wire is cut into two equal pieces and connected parallel to the same power supply. In this case, power dissipation is P2. The ratio of `"P"_2/"P"_1` is

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उत्तर

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Current Electricity - Evaluation [पृष्ठ ११८]

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सामाचीर कलवी Physics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 2 Current Electricity
Evaluation | Q I. 7. | पृष्ठ ११८

संबंधित प्रश्न

A wire of resistance 9 ohm having length 30 cm is tripled on itself. What is its new resistance?


A wire has a length of 2.0 m and a resistance of 5.0 Ω. Find the electric field existing inside the wire if it carries a current of 10 A.


State Ohm’s law. Is it always true?

Define one ohm.

The filament of a bulb takes a current 100 mA when potential difference across it is 0.2 V. When the potential difference across it becomes 1.0 V, the current becomes 400 mA. Calculate the resistance of filament in each case and account for the difference.


State and define Ohm’s law.


An electronics hobbyist is building a radio which requires 150 Ω in her circuit, but she has only 220 Ω, 79 Ω, and 92 Ω resistors available. How can she connect the available resistors to get the desired value of resistance?


Two cells each of 5V are connected in series across an 8Ω resistor and three parallel resistors of 4Ω, 6Ω, and 12Ω. Draw a circuit diagram for the above arrangement. Calculate

  1. the current drawn from the cell
  2. current through each resistor

Why should an ammeter have low resistance?


The circuit depicted in the figure is employed for studying Ohm’s Law. Instead of using a standard resistor, a student opts for a glass tube filled with mercury (tube 1), connected to the circuit through two electrodes, E1 and E2. He records the readings of the ammeter and voltmeter, thereby calculating the resistance. The student repeats the experiment by substituting tube 1 with tube 2, where the same amount of mercury fills tube 2.

Neglecting internal resistance of the cell use (> or < or =) to compare:

  1. the resistance in both the cases.
  2. the voltmeter readings in both the cases.
  3. the specific resistance in both the cases.

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