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A Piece of Equipment Cost a Certain Factory Rs 600,000. If It Depreciates in Value, 15% the First, 13.5% the Next Year, 12% the Third Year, and So On. What Will Be Its Value at the End of 10 Years, - Mathematics

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प्रश्न

A piece of equipment cost a certain factory Rs 600,000. If it depreciates in value, 15% the first, 13.5% the next year, 12% the third year, and so on. What will be its value at the end of 10 years, all percentages applying to the original cost?

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उत्तर

Given: A piece of equipment cost a certain factory is 600,000

To find: Value of the equipment at the end of 10 years

It depreciates 15%, 13.5%, 12% in 1st, 2nd, 3rd year and so on.

This means the price of the equipment is depreciating in an A.P.

A.P. will be 15, 13.5, 12,…………………………up to 10 terms

Hence a = 15, d = 13.5 – 15 = –1.5

Formula used:

`S_n = n/2 {2a +(n-1)d}`

where a is first term, d is common difference and n is number of terms in an A.P.

Therefore,

Total percentage of depreciation in 10 years,

`S_10 =10/2{2xx15+(10-1)xx-1.5}`

⇒ S10 = 5(30+9× -1.5) 

⇒ S10 = 5(30 -13.5 )

⇒ S10 = 5(16.5)

⇒ S10 = 82.5

Value of the equipment at the end of 10 years,

 `= (100-"Depreciation"%)/100 xx "cost of equipment"`

`=(100-82.5)/100 xx 600000`

 `= 175/10 xx 6000`

 =175 × 600

= 105000

Hence, value of equipment at the end of 10 years is Rs. 105000 

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अध्याय 19: Arithmetic Progression - Exercise 19.7 [पृष्ठ ४९]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 19 Arithmetic Progression
Exercise 19.7 | Q 7 | पृष्ठ ४९

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