Advertisements
Advertisements
प्रश्न
A body projected vertically up with a velocity of 10 m/s reaches a height of 20 m. If it is projected with a velocity of 20 m/s, then the maximum height reached by the body is:
विकल्प
20 m
10 m
80 m
40 m
Advertisements
उत्तर
80 m
Explanation:
Initial velocity = u = 10 m/s
Height = Distance = S = 20 m
At highest point, Final velocity = v = 0
Acceleration = (a) = ?
Case − I
v2 − u2 = 2aS
(0)2 − (10)2 = 2a (20)
a = `-100/40` = −2.5 ms−2
Case – II
u = 20 m/s; v = 0
a = −2.5 ms−2; S = h /
v2 − u2 = 2aS
(0)2 − (20)2 = 2(−2.5)h
h = `400/5` = 80 m
APPEARS IN
संबंधित प्रश्न
If a sprinter runs a distance of 100 metres in 9.83 seconds, calculate his average speed in km/h.
A train starting from rest moves with a uniform acceleration of 0.2 m/s2 for 5 minutes. Calculate the speed acquired and the distance travelled in this time.
The tip of seconds’ hand of a dock takes 60 seconds to move once on the circular dial of the clock. If the radius of the dial of the clock be 10.5 cm, calculate the speed of the tip of the seconds’ hand of the clock. `("Given" π= 22/7)`.
Which of the following could not be a unit of speed?
When is a body said to be in motion?
What do you mean by motion in one direction?
A train travels with a speed of 60 km h-1 from station A to station B and then comes back with a speed 80 km h-1 from station B to station A. Find -
- The average speed
- The average velocity of the train.
How many variables are present in each equation of motion?
Derive th e equation of motion.
S = ut+ `1/2` at2,
Where the symbols have their usual meanings
A motorcyclist drives from A to B with a uniform speed of 30 km h–1 and returns back with a speed of 20 km h–1. Find its average speed.
