Advertisements
Advertisements
प्रश्न
A body moves from rest with uniform acceleration and travels 270 m in 3 s. Find the velocity of the body at 10 s after the start.
Advertisements
उत्तर
Initial velocity u = 0 m/s
Distance travelled s = 270 m
Time taken to travel s distance = 3 s
Let 'a' be the uniform acceleration.
Using the second equation of motion,
S = ut + (1/2) at2
We get,
270 = 0 + (1/2) a (3)2
270 = 9a/2
a = 60 m/s2
Let v be the velocity of the body 10 s after the start.
Using the first equation of motion, we get
v = u + at
v = 0 + (60)(10) = 600 m/s-1
APPEARS IN
संबंधित प्रश्न
Name the physical quantity which gives us an idea of how slow or fast a body is moving.
In addition to speed, what else should we know to predict the position of a moving body ?
Arrange the following speed in increasing order (keeping the least speed first):
A bicycle moving with a speed of 200 m/min.
Arrange the following speed in increasing order (keeping the least speed first
A scooter moving with a speed of 30 km/h.
A car travels 100 km at a speed of 60 km/h and returns with a speed of 40 km/h. Calculate the average speed for the whole journey.
Give one example of a motion where an object does not change its speed but its direction of motion changes continuously.
Give an example of the motion of a body moving with a constant speed but with a variable velocity. Draw a diagram to represent such a motion.
Arrange the following speeds in increasing order.
10 m s-1, 1 km min-1 and 18 km h-1.
A train takes 2 h to reach station B from station A, and then 3 h to return from station B to station A. The distance between the two stations is 200 km. Find:
The average speed,
The average velocity of the train.
A motorcyclist drives from A to B with a uniform speed of 30 km h–1 and returns back with a speed of 20 km h–1. Find its average speed.
