Question

A body moves from rest with uniform acceleration and travels 270 m in 3 s. Find the velocity of the body at 10 s after the start.

Answer 1

Initial velocity u = 0 m/s

Distance travelled s = 270 m

Time taken to travel s distance = 3 s

Let 'a' be the uniform acceleration.

Using the second equation of motion,

S = ut + (1/2) at²

We get,

270 = 0 + (1/2) a (3)²

270 = 9a/2

a = 60 m/s²

Let v be the velocity of the body 10 s after the start.

Using the first equation of motion, we get

v = u + at

v = 0 + (60)(10) = 600 m/s^-1