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प्रश्न
\[\int\sqrt{\frac{1 + \cos 2x}{1 - \cos 2x}} dx\]
योग
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उत्तर
\[\int\sqrt{\frac{1 + \cos2x}{1 - \cos2x}}dx\]
\[ = \int\sqrt{\frac{2 \cos^2 x}{2 \sin^2 x}}dx\]
\[ = \int\ \text{cot x dx}\]
\[ = \text{ln} \left| \text{sin x} \right| + C\]
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