हिंदी

∫ X √ X 4 + a 4 D X - Mathematics

Advertisements
Advertisements

प्रश्न

\[\int\frac{x}{\sqrt{x^4 + a^4}} dx\]
योग
Advertisements

उत्तर

 

` ∫  {x  dx}/{\sqrt{x^4 + a^4}} `

 ` ∫  {x  dx}/\sqrt{(x^2)^2 + (a^2)^2}`
` \text{  let}   x^2 = t `
\[ \Rightarrow\text{  2x dx } = dt\]
\[ \Rightarrow\text{  x dx } = \frac{dt}{2}\]
Now,  ` ∫  {x  dx}/\sqrt{(x^2)^2 + (a^2)^2}`
\[ = \frac{1}{2}\int\frac{dt}{\sqrt{t^2 + \left( a^2 \right)^2}}\]
\[ = \frac{1}{2} \text{ log }\left| t + \sqrt{t^2 + a^4} \right| + C\]
\[ = \frac{1}{2} \text{ log }\left| x^2 + \sqrt{x^4 + a^4} \right| + C\]

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 19: Indefinite Integrals - Exercise 19.18 [पृष्ठ ९८]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 12
अध्याय 19 Indefinite Integrals
Exercise 19.18 | Q 1 | पृष्ठ ९८

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

\[\int\left( 3x\sqrt{x} + 4\sqrt{x} + 5 \right)dx\]

\[\int\left( x^e + e^x + e^e \right) dx\]

\[\int\frac{x + 3}{\left( x + 1 \right)^4} dx\]

\[\int\frac{1 + \cos x}{1 - \cos x} dx\]

\[\int\frac{1}{\sqrt{1 - \cos 2x}} dx\]

` ∫  {sec  x   "cosec " x}/{log  ( tan x) }`  dx


\[\int\frac{\sin \left( \text{log x} \right)}{x} dx\]

\[\int\frac{\text{sin }\left( \text{2 + 3 log x }\right)}{x} dx\]

\[\int\frac{x^2 + 3x + 1}{\left( x + 1 \right)^2} dx\]

\[\int \cot^n {cosec}^2 \text{ x dx } , n \neq - 1\]

\[\int \cos^7 x \text{ dx  } \]

Evaluate the following integrals:

\[\int\cos\left\{ 2 \cot^{- 1} \sqrt{\frac{1 + x}{1 - x}} \right\}dx\]

\[\int\frac{1}{a^2 - b^2 x^2} dx\]

\[\int\frac{x^2 - 1}{x^2 + 4} dx\]

\[\int\frac{1}{4 x^2 + 12x + 5} dx\]

\[\int\frac{x^2}{x^6 + a^6} dx\]

\[\int\frac{\cos x - \sin x}{\sqrt{8 - \sin2x}}dx\]

\[\int\frac{x^2 + x + 1}{x^2 - x} dx\]

\[\int\sqrt{\frac{1 - x}{1 + x}} \text{ dx }\]

\[\int\frac{1}{3 + 2 \cos^2 x} \text{ dx }\]

\[\int\frac{1}{\sqrt{3} \sin x + \cos x} dx\]

\[\int\frac{4 \sin x + 5 \cos x}{5 \sin x + 4 \cos x} \text{ dx }\]

\[\int\left( x + 1 \right) \text{ e}^x \text{ log } \left( x e^x \right) dx\]

\[\int \cos^{- 1} \left( \frac{1 - x^2}{1 + x^2} \right) \text{ dx }\]

\[\int\frac{x^2 + x - 1}{x^2 + x - 6} dx\]

\[\int\frac{5 x^2 - 1}{x \left( x - 1 \right) \left( x + 1 \right)} dx\]

\[\int\frac{x^2 + 6x - 8}{x^3 - 4x} dx\]

\[\int\frac{5 x^2 + 20x + 6}{x^3 + 2 x^2 + x} dx\]

\[\int\frac{2x + 1}{\left( x - 2 \right) \left( x - 3 \right)} dx\]

\[\int\sqrt{\cot \text{θ} d  } \text{ θ}\]

\[\int\frac{x}{\left( x - 3 \right) \sqrt{x + 1}} dx\]

\[\int\frac{1}{\left( \sin^{- 1} x \right) \sqrt{1 - x^2}} \text{ dx} \]

\[\int\frac{x^2}{\left( x - 1 \right)^3} dx\]

\[\int\frac{1}{4 x^2 + 4x + 5} dx\]

\[\int\frac{1}{1 - x - 4 x^2}\text{  dx }\]

\[\int\frac{x^3}{\sqrt{x^8 + 4}} \text{ dx }\]


\[\int\frac{1}{1 - 2 \sin x} \text{ dx }\]

\[\int\frac{1}{\sin x + \sin 2x} \text{ dx }\]

\[\int\sqrt{x^2 - a^2} \text{ dx}\]

\[\int\frac{\cot x + \cot^3 x}{1 + \cot^3 x} \text{ dx}\]

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×