हिंदी

\[\Int\Left( 3x\Sqrt{X} + 4\Sqrt{X} + 5 \Right)Dx\] - Mathematics

Advertisements
Advertisements

प्रश्न

\[\int\left( 3x\sqrt{x} + 4\sqrt{x} + 5 \right)dx\]
योग
Advertisements

उत्तर

\[\int\left( 3x\sqrt{x} + 4\sqrt{x} + 5 \right)dx\]
\[ = \int\left( 3 x^1 \cdot x^\frac{1}{2} + 4 x^\frac{1}{2} + 5 \right)dx\]
\[ = 3\int x^\frac{3}{2} dx + 4\int x^\frac{1}{2} dx + 5 ∫dx\]
\[ = 3\left[ \frac{x^\frac{3}{2} + 1}{\frac{3}{2} + 1} \right] + 4\left[ \frac{x^\frac{1}{2} + 1}{\frac{1}{2} + 1} \right] + 5x + C\]
\[ = 3 \times \frac{2}{5} x^\frac{5}{2} + 4 \times \frac{2}{3} x^\frac{3}{2} + 5x + C\]
\[ = \frac{6}{5} x^\frac{5}{2} + \frac{8}{3} x^\frac{3}{2} + 5x + C\]

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 19: Indefinite Integrals - Exercise 19.02 [पृष्ठ १४]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 12
अध्याय 19 Indefinite Integrals
Exercise 19.02 | Q 1 | पृष्ठ १४

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

\[\int\frac{\left( 1 + x \right)^3}{\sqrt{x}} dx\] 

\[\int\frac{\sin^2 x}{1 + \cos x}   \text{dx} \]

\[\int\frac{1}{\sqrt{x + 1} + \sqrt{x}} dx\]

\[\int \sin^2\text{ b x dx}\]

` ∫   sin x  \sqrt (1-cos 2x)    dx `

 


\[\int\sqrt{\frac{1 + \cos 2x}{1 - \cos 2x}} dx\]

\[\int\frac{x}{\sqrt{x^2 + a^2} + \sqrt{x^2 - a^2}} dx\]

\[\int\frac{1}{x^2 \left( x^4 + 1 \right)^{3/4}} dx\]

` ∫  sec^6   x  tan    x   dx `

\[\int {cosec}^4  \text{ 3x } \text{ dx } \]

\[\int\frac{1}{4 x^2 + 12x + 5} dx\]

\[\int\frac{x + 2}{2 x^2 + 6x + 5}\text{  dx }\]

\[\int\frac{\left( 3\sin x - 2 \right)\cos x}{13 - \cos^2 x - 7\sin x}dx\]

\[\int\frac{1}{\cos 2x + 3 \sin^2 x} dx\]

\[\int\frac{1}{2 + \sin x + \cos x} \text{ dx }\]

\[\int\frac{1}{1 - \tan x} \text{ dx }\]

\[\int x^3 \text{ log x dx }\]

\[\int x \text{ sin 2x dx }\]

\[\int x\left( \frac{\sec 2x - 1}{\sec 2x + 1} \right) dx\]

\[\int x \sin x \cos 2x\ dx\]

\[\int \sin^3 \sqrt{x}\ dx\]

\[\int x \cos^3 x\ dx\]

\[\int \sin^{- 1} \sqrt{\frac{x}{a + x}} \text{ dx }\]

\[\int\frac{x^3 \sin^{- 1} x^2}{\sqrt{1 - x^4}} \text{ dx }\]

\[\int e^x \left( \cos x - \sin x \right) dx\]

\[\int\left\{ \tan \left( \log x \right) + \sec^2 \left( \log x \right) \right\} dx\]

\[\int x\sqrt{x^4 + 1} \text{ dx}\]

\[\int\sqrt{x^2 - 2x} \text{ dx}\]

\[\int\frac{x}{\left( x^2 - a^2 \right) \left( x^2 - b^2 \right)} dx\]

\[\int\frac{1}{\cos x \left( 5 - 4 \sin x \right)} dx\]

\[\int\frac{4 x^4 + 3}{\left( x^2 + 2 \right) \left( x^2 + 3 \right) \left( x^2 + 4 \right)} dx\]

\[\int\frac{1}{\left( 2 x^2 + 3 \right) \sqrt{x^2 - 4}} \text{ dx }\]

\[\int\frac{x}{4 + x^4} \text{ dx }\] is equal to

\[\int e^x \left\{ f\left( x \right) + f'\left( x \right) \right\} dx =\]
 

\[\int\frac{x + 2}{\left( x + 1 \right)^3} \text{ dx }\]


\[\int\frac{x + 1}{x^2 + 4x + 5} \text{  dx}\]

\[\int \tan^5 x\ \sec^3 x\ dx\]

\[\int\sqrt{1 + 2x - 3 x^2}\text{  dx } \]

\[\int \left( \sin^{- 1} x \right)^3 dx\]

\[\int\frac{x^2 + 1}{x^2 - 5x + 6} \text{ dx }\]
 

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×