हिंदी

∫ E X X { X ( Log X ) 2 + 2 Log X } D X - Mathematics

Advertisements
Advertisements

प्रश्न

\[\int\frac{e^x}{x}\left\{ \text{ x }\left( \log x \right)^2 + 2 \log x \right\} dx\]
योग
Advertisements

उत्तर

\[\text{ Let I }= \int\frac{e^x}{x}\left[ x \left( \log x \right)^2 + 2\log x \right]dx\]

\[ = \int e^x \left[ \left( \log x \right)^2 + \frac{2\log x}{x} \right]dx\]

\[Here, f(x) = \left( \log x \right)^2 \]

\[ \Rightarrow f'(x) = \frac{2\log x}{x}\]

\[\text{ put  e}^x f(x) = t\]

\[ \Rightarrow e^x \left( \log x \right)^2 = t\]

\[\text{ Diff   both    sides   w . r . t x }\]

\[\left[ e^x \left( \log  x \right)^2 + e^x \frac{2\log x}{x} \right]dx = dt\]

\[ \therefore I = \int dt\]

\[ = t + C\]

\[ = e^x \left( \log x \right)^2 + C\]

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 19: Indefinite Integrals - Exercise 19.26 [पृष्ठ १४३]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 12
अध्याय 19 Indefinite Integrals
Exercise 19.26 | Q 17 | पृष्ठ १४३

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

\[\int \tan^{- 1} \left( \frac{\sin 2x}{1 + \cos 2x} \right) dx\]

\[\int\frac{x^3 - 3 x^2 + 5x - 7 + x^2 a^x}{2 x^2} dx\]

\[\int\frac{1}{\sqrt{x + a} + \sqrt{x + b}} dx\]

\[\int\sin x\sqrt{1 + \cos 2x} dx\]

\[\int\frac{1 + \cos 4x}{\cot x - \tan x} dx\]

\[\int\frac{x^3}{x - 2} dx\]

\[\int\frac{3x + 5}{\sqrt{7x + 9}} dx\]

`∫     cos ^4  2x   dx `


\[\int\frac{e^{3x}}{e^{3x} + 1} dx\]

\[\int\frac{\cos 4x - \cos 2x}{\sin 4x - \sin 2x} dx\]

\[\int\frac{\tan x}{\sqrt{\cos x}} dx\]

\[\int\frac{1}{1 + \sqrt{x}} dx\]

` ∫  sec^6   x  tan    x   dx `

\[\int \cos^5 x \text{ dx }\]

Evaluate the following integrals:

\[\int\frac{x^7}{\left( a^2 - x^2 \right)^5}dx\]

\[\int\frac{e^{3x}}{4 e^{6x} - 9} dx\]

\[\int\frac{\sin 8x}{\sqrt{9 + \sin^4 4x}} dx\]

\[\int\frac{\cos 2x}{\sqrt{\sin^2 2x + 8}} dx\]

\[\int\frac{x + 2}{\sqrt{x^2 + 2x - 1}} \text{ dx }\]

\[\int\frac{2x + 3}{\sqrt{x^2 + 4x + 5}} \text{ dx }\]

\[\int\frac{1}{3 + 2 \cos^2 x} \text{ dx }\]

\[\int\frac{1}{3 + 4 \cot x} dx\]

\[\int\frac{\log \left( \log x \right)}{x} dx\]

\[\int \sin^{- 1} \left( \frac{2x}{1 + x^2} \right) \text{ dx }\]

\[\int\frac{x^2 \tan^{- 1} x}{1 + x^2} \text{ dx }\]

\[\int x^3 \tan^{- 1}\text{  x dx }\]

\[\int \sin^3 \sqrt{x}\ dx\]

\[\int\left\{ \tan \left( \log x \right) + \sec^2 \left( \log x \right) \right\} dx\]

\[\int\sqrt{x^2 - 2x} \text{ dx}\]

\[\int x\sqrt{x^2 + x} \text{  dx }\]

\[\int(2x + 5)\sqrt{10 - 4x - 3 x^2}dx\]

\[\int\frac{x^2 + 1}{\left( 2x + 1 \right) \left( x^2 - 1 \right)} dx\]

\[\int\frac{1}{\left( x^2 + 1 \right) \left( x^2 + 2 \right)} dx\]

Evaluate the following integral:

\[\int\frac{x^2}{1 - x^4}dx\]

\[\int\frac{x}{\left( x^2 + 2x + 2 \right) \sqrt{x + 1}} \text{ dx}\]

\[\int\text{ cos x  cos  2x   cos  3x  dx}\]


\[\int\frac{1}{4 \sin^2 x + 4 \sin x \cos x + 5 \cos^2 x} \text{ dx }\]


\[\int\sqrt{1 + 2x - 3 x^2}\text{  dx } \]

\[\int\frac{5 x^4 + 12 x^3 + 7 x^2}{x^2 + x} dx\]


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×