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∫ 1 √ 3 X 2 + 5 X + 7 D X - Mathematics

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प्रश्न

\[\int\frac{1}{\sqrt{3 x^2 + 5x + 7}} dx\]
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उत्तर

\[\int\frac{dx}{\sqrt{3 x^2 + 5x + 7}}\]
\[ = \int\frac{dx}{\sqrt{3\left( x^2 + \frac{5}{3}x + \frac{7}{3} \right)}}\]
\[ = \frac{1}{\sqrt{3}}\int\frac{dx}{\sqrt{x^2 + \frac{5}{3}x + \left( \frac{5}{6} \right)^2 - \left( \frac{5}{6} \right)^2 + \frac{7}{3}}}\]
\[ = \frac{1}{\sqrt{3}}\int\frac{dx}{\sqrt{\left( x + \frac{5}{6} \right)^2 - \frac{25}{36} + \frac{7}{3}}}\]
\[ = \frac{1}{\sqrt{3}}\int\frac{dx}{\sqrt{\left( x + \frac{5}{6} \right)^2 + \frac{- 25 + 84}{36}}}\]


\[ = \frac{1}{\sqrt{3}}\int\frac{dx}{\sqrt{\left( x + \frac{5}{6} \right)^2 + \frac{59}{36}}}\]
\[ = \frac{1}{\sqrt{3}}\int\frac{dx}{\sqrt{\left( x + \frac{5}{6} \right)^2 + \left( \frac{\sqrt{59}}{36} \right)^2}}\]
\[ = \frac{1}{\sqrt{3}} \log \left| x + \frac{5}{6} + \sqrt{\left( x + \frac{5}{6} \right)^2 + \frac{59}{36}} \right| + C\]
\[ = \frac{1}{\sqrt{3}} \log \left| x + \frac{5}{6} + \sqrt{x^2 + \frac{5}{3}x + \frac{7}{3}} \right| + C\]

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अध्याय 19: Indefinite Integrals - Exercise 19.17 [पृष्ठ ९३]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 19 Indefinite Integrals
Exercise 19.17 | Q 4 | पृष्ठ ९३

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