English

Selina solutions for Concise Mathematics [English] Class 10 ICSE chapter 24 - Measure of Central Tendency (Mean, Median, Quartiles and Mode) [Latest edition]

Advertisements

Chapters

Selina solutions for Concise Mathematics [English] Class 10 ICSE chapter 24 - Measure of Central Tendency (Mean, Median, Quartiles and Mode) - Shaalaa.com
Advertisements

Solutions for Chapter 24: Measure of Central Tendency (Mean, Median, Quartiles and Mode)

Below listed, you can find solutions for Chapter 24 of CISCE Selina for Concise Mathematics [English] Class 10 ICSE.


EXERCISE 24 (A)EXERCISE 24 (B)EXERCISE 24 (C)TEST YOURSELF
EXERCISE 24 (A) [Pages 368 - 369]

Selina solutions for Concise Mathematics [English] Class 10 ICSE 24 Measure of Central Tendency (Mean, Median, Quartiles and Mode) EXERCISE 24 (A) [Pages 368 - 369]

Multiple Choice Type: Choose the correct answer from the options given below.

1. (a)Page 368

The mean of 5 variables is 20. If four of them are 15, 25, 10 and 12; the fifth variable is ______.

  • 38

  • 60

  • 48

  • 28

1. (b)Page 368

The mean height of 5 students is 140 cm. If height of one student is 156 cm, the mean height of the remaining students is ______.

  • 74 cm

  • 136 cm

  • 16 cm

  • 80 cm

1. (c)Page 368

The mean age of eight boys is 16 years. If two more boys, with ages 18 years and 14 years, join them, the resulting mean age is ______.

  • 18 years

  • 14 years

  • 16 years

  • 32 years

1. (d)Page 368

The mean value of 15 numbers is 20. If one of these numbers is wrongly taken as 45 instead of 15, the correct mean is ______.

  • 30

  • 15

  • 20

  • 18

1. (e)Page 368

The mean of the given frequency distribution is:

x 30 20
f 15 5
  • \[\frac{30}{15}+\frac{20}{5}\]

  • \[\frac{30}{15}-\frac{20}{5}\]

  • \[\frac{550}{20}=27.5\]

  • \[\frac{50}{20}=2 \cdot 5\]

2.Page 368

Marks obtained (in mathematics) by 9 students are given below:

60, 67, 52, 76, 50, 51, 74, 45 and 56  

  1. Find the arithmetic mean.
  2. If marks of each student be increased by 4; what will be the new value of arithmetic mean?
3.Page 368
  1. Find the mean of 7, 11, 6, 5 and 6.
  2. If each number given in (a) is diminished by 2; find the new value of mean.
4.Page 368

If the mean of 6, 4, 7, ‘a’ and 10 is 8. Find the value of ‘a’ 

5.Page 368

The mean of the number 6, ‘y’, 7, ‘x’ and 14 is 8. Express ‘y’ in terms of ‘x’. 

6.Page 368

The ages of 40 students are given in the following table : 

 Age (in years)  12  13 14 15 16 17 18
 Frequency 2 4 6 9 8 7 4

Find the arithmetic mean.

7.Page 368

If 69.5 is the mean of 72, 70, ‘x’, 62, 50, 71, 90, 64, 58 and 82, find the value of ‘x’.

8.Page 368

The following table gives the heights of plants in centimeter. If the mean height of plants is 60.95 cm; find the value of ‘f’. 

Height (cm)  50 55 58 60 65 70 71
No. of plants  2 4 10 f 5 4 3
9.Page 369

From the data given below, calculate the mean wage, correct to the nearest rupee.

Category  A B C D E F
 Wages (Rs/day) 50 60 70 80 90 100
No. of workers 2 4 8 12 10 6
  1. If the number of workers in each category is doubled, what would be the new mean wage? 
  2. If the wages per day in each category are increased by 60%; what is the new mean wage? 
  3. If the number of workers in each category is doubled and the wages per day per worker are reduced by 40%, what would be the new mean wage?
10.Page 369

The contents of 100 match boxes were checked to determine the number of matches they contained.

No. of matches 35 36 37 38 39 40 41
 No. of boxes 6 10 18 25 21 12 8
  1. Calculate, correct to one decimal place, the mean number of matches per box. 
  2. Determine, how many extra matches would have to be added to the total contents of the 100 boxes to bring the mean up to exactly 39 matches.
11.Page 369

If the mean of the following distribution is 3, find the value of p.

x 1 2 3 5 p + 4
f 9 6 9 3 6
12.Page 369

In the following table, Σf = 200 and mean = 73. Find the missing frequencies f1, and f2.

x 0 50 100 150 200 250
f 46 f1 f2 25 10 5
13.Page 369

Find the arithmetic mean (correct to the nearest whole number) by using step-deviation method.

x 5 10 15 20 25 30 35 40 45 50
f 20 43 75 67 72 45 39 9 8 6
14.Page 369

Find the mean (correct to one place of decimal) by using short-cut method.

x

40

41

43

45

46

49

50

f

14

28

38

50

40

20

10

EXERCISE 24 (B) [Pages 374 - 376]

Selina solutions for Concise Mathematics [English] Class 10 ICSE 24 Measure of Central Tendency (Mean, Median, Quartiles and Mode) EXERCISE 24 (B) [Pages 374 - 376]

Multiple Choice Type: Choose the correct answer from the options given below.

1. (a)Page 374

The mean of given observations is:

C.I. 30-40 40-50
f 2 3
  • 41

  • 27

  • 71

  • 91

1. (b)Page 374

For data given in the adjoining table, the mean is:

C.I. f x
0-10 5  
10-20 10  
20-30 10  
  • 17

  • 27

  • 25

  • 60

1. (c)Page 374

The mean of observations, given in the adjoining table, is 24, the value of a is:

x f
10 10
20 a
30 30
  • 20

  • 30

  • 10

  • 25

1. (d)Page 375

If the mean of the data given in adjoining table is 20, the relation between x1 and x2 is:

x f
10 x1
20 20
30 x2
  • x1 + x2 = 30

  • x1 − x2 = 15

  • x1 − x2 = 0

  • x1 + x2 = 20

1. (e)Page 375

The mean of data, represented by given diagram, is:

The image displays a statistical histogram featuring a vertical frequency axis ranging from $0$ to $40$ with a break or kink at the origin, a horizontal class interval (C.I.) axis starting from $40$ up to $60$, and two rectangular bars representing frequency distributions across the class intervals $40\text{--}50$ (frequency $40$) and $50\text{--}60$ (frequency $10$).

  • 53

  • 47

  • 42

  • 51

2.Page 375

The following table gives the age of 50 student of a class. Find the arithmetic mean of their ages. 

Age-years 16 – 18 18 – 20 20 – 22 22 – 24 24 – 26
No. of students  2 7 21 17 3
3. (i)Page 375

The following are the marks obtained by 70 boys in a class test: 

 Marks   No. of boys 
30 – 40 10
40 – 50 12
50 – 60 14
60 – 70 12
70 – 80 9
80 – 90 7
90 – 100 6

Calculate the mean by: 

Short-cut method

3. (ii)Page 375

The following are the marks obtained by 70 boys in a class test:

 Marks   No. of boys 
30 – 40 10
40 – 50 12
50 – 60 14
60 – 70 12
70 – 80 9
80 – 90 7
90 – 100 6

Calculate the mean by:  

Step-deviation method

4.Page 375

Find mean by step-deviation method:

 C.I. 63 – 70 70 – 77 77 – 84 84 – 91 91 – 98 98 – 105 105 – 112
 Frequency  9 13 27 38 32 16 15
5.Page 375

The mean of the following distribution is `21 1/7`. Find the value of ‘f’.

C.I. 0 – 10 10 – 20 20 – 30 30 – 40 40 – 50
Frequency  8 22 31 f 2
6.Page 375

Using the information given in the adjoining histogram, calculate the mean. 

7.Page 376

If the mean of the following observations is 54, find the value of p.

 Class 0 – 20 20 – 40 40 – 60 60 – 80 80 – 100
 Frequency 7 p 10 9 13
8.Page 376

The mean of the following distribution is 62.8 and the sum of all the frequencies is 50. Find the missing frequencies f1 and f2.

Class  0 – 20 20 – 40 40 – 60 60 – 80 80 – 100 100 – 120
Frequency 5 f1 10  f2 7 8
9.Page 376

Calculate the mean of the distribution, given below using the short cut method:

Marks 11 – 20 21 – 30 31 – 40 41 – 50 51 – 60 61 – 70 71 – 80
No. of students 2 6 10 12 9 7 4
EXERCISE 24 (C) [Pages 385 - 387]

Selina solutions for Concise Mathematics [English] Class 10 ICSE 24 Measure of Central Tendency (Mean, Median, Quartiles and Mode) EXERCISE 24 (C) [Pages 385 - 387]

Multiple Choice Type: Choose the correct answer from the options given below.

1. (a)Page 385

The median of 18, 29, 15, 14 and 21 is ______.

  • 15

  • 18

  • 29

  • 21

1. (b)Page 385

The median of 3, 8, 11, 2, 16, 4, 0 and 6 is ______.

  • 6

  • 9

  • 5

  • 8

1. (c)Page 386

Numbers 5, 15, 20, x, 28, 30, 35 are in ascending order and have median = 23; then the value of x is ______.

  • 24

  • 29

  • 17.5

  • 23

1. (d)Page 386

For numbers 10, 20, 30, 40, 50, 60, 70 and 80; the inter-quartile range is ______.

  • 20 + 60

  • 60 - 30

  • 60 - 20

  • 50 - 10

1. (e)Page 386

From the given diagram, the modal class is:

The image displays a statistical histogram featuring a vertical frequency axis with a break or kink at the origin, a horizontal class interval (C.I.) axis ranging from $0$ up to $70$, and rectangular bars representing frequency distributions across the class intervals $30\text{--}40$, $40\text{--}50$, $50\text{--}60$, and $60\text{--}70$.

  • 30-40

  • 40-50

  • 50-60

  • 60-70

2.Page 386

A student got the following marks in 9 questions of a question paper.

3, 5, 7, 3, 8, 0, 1, 4 and 6.

Find the median of these marks. 

3.Page 386

The weights (in kg) of 10 students of a class are given below:

21, 28.5, 20.5, 24, 25.5, 22, 27.5, 28, 21 and 24.

Find the median of their weights. 

4.Page 386

The marks obtained by 19 students of a class are given below:

27, 36, 22, 31, 25, 26, 33, 24, 37, 32, 29, 28, 36, 35, 27, 26, 32, 35 and 28.

Find:

  1. Median
  2. Lower quartile
  3. Upper quartile
  4. Inter-quartile range
5.Page 386

The weight of 60 boys are given in the following distribution table:

Weight (kg) 37 38 39 40 41
No. of boys 10 14 18 12 6

Find:

  1. Median 
  2. Lower quartile 
  3. Upper quartile 
  4. Inter-quartile range  
6.Page 386

From the following cumulative frequency table, draw ogive and then use it to find:

  1. Median 
  2. Lower quartile 
  3. Upper quartile 
Marks (less than) 10 20 30 40 50 60 70 80 90 100
Cumulative frequency 5 24 37 40 42 48 70 77 79 80 
7.Page 386

In a school, 100 pupils have heights as tabulate below: 

 Height (in cm)  No. of pupils 
121 – 130 12
131 – 140 16
141 – 150 30
151 – 160 20
161 – 170 14
171 – 180 8

Find the median height by drawing an ogive.

8.Page 386

Find the mode of following data, using a histogram: 

Class  0 – 10 10 – 20 20 – 30 30 – 40 40 – 50
Frequency 5 12 20 9 4
9.Page 386

The following table shows the expenditure of 60 boys on books. Find the mode of their expenditure:  

 Expenditure (Rs)  No. of students 
20 – 25 4
25 – 30 7
30 – 35 23
35 – 40 18
40 – 45 6
45 – 50 2
10. (i)Page 387

A boy scored following marks in various class tests during a term; each test being marked out of 20.

15, 17, 16, 7, 10, 12, 14, 16, 19, 12 and 16 

What are his modal marks? 

10. (ii)Page 387

A boy scored following marks in various class tests during a term; each test being marked out of 20.

15, 17, 16, 7, 10, 12, 14, 16, 19, 12 and 16 

What are his median marks? 

10. (iii)Page 387

A boy scored following marks in various class tests during a term; each test being marked out of 20.

15, 17, 16, 7, 10, 12, 14, 16, 19, 12 and 16  

What are his total marks?

10. (iv)Page 387

A boy scored following marks in various class tests during a term; each test being marked out of 20.

15, 17, 16, 7, 10, 12, 14, 16, 19, 12 and 16

 What are his mean marks?

11.Page 387

At a shooting competition the score of a competitor were as given below:

Score 0 1 2 3 4 5
No. of shots  0 3 6 4 7 5
  1. What was his modal score? 
  2. What was his median score? 
  3. What was his total score?
  4. What was his mean score?
TEST YOURSELF [Pages 387 - 391]

Selina solutions for Concise Mathematics [English] Class 10 ICSE 24 Measure of Central Tendency (Mean, Median, Quartiles and Mode) TEST YOURSELF [Pages 387 - 391]

Multiple Choice Type: Choose the correct answer from the options given below.

1. (a)Page 387

The mean of numbers in A.P. 2, 4, 6, 8, …, 40 is ______.

  • `(40+2)/2`

  • `20/2(2+40)`

  • `10/2(2+40)`

  • 840

1. (b)Page 387

The median of 10, 12, 9, 8, 12, 13, 8, 15 and 12 is ______.

  • 12

  • `(10+12)/2`

  • `(12+13)/2`

  • 13

1. (c)Page 387

The numbers 10, 12, 14, 16, 17 and x are in ascending order. If the mean and median of these observations are same, the value of x is ______.

  • 16

  • 14

  • 54

  • 21

1. (d)Page 387

The median of first six prime numbers is ______.

  • 5

  • 7

  • 6

  • 7.5

1. (e)Page 387

The inter quartile range for the given ogive is:

  • 42

  • 32

  • 44

  • 54

1. (f)Page 387

The mean age of nine boys is 28 years and if one new boy joins them the mean age increases by one.

Assertion (A): The age of new boy is (29 × 10 − 28 × 9) years.

Reason (R): The age of new boy is (29 − 28) × 10 years.

  • A is true, R is false.

  • A is false, R is true.

  • Both A and R are true and R is the correct reason for A.

  • Both A and R are true and R is the incorrect reason for A.

1. (g)Page 388

Data = 37, 41, 56, 62, 70, 74, 81, 89, 95 and 90.

Assertion (A): Median = 72.

Reason (R): If number of data(n) is odd, the median = `((n+1)/2)^(th)` term.

  • A is true, R is false.

  • A is false, R is true.

  • Both A and R are true and R is the correct reason for A.

  • Both A and R are true and R is the incorrect reason for A.

1. (h)Page 388
C.I. 0 - 10 10 - 20 20 - 30
Frequency 15 25 b
Cumulative frequency 15 a 50

Assertion (A): a = 15 + 25 = 40;
b = 50 − a

Reason (R): a + 15 = 25
and b = 50 − 10

  • A is true, R is false.

  • A is false, R is true.

  • Both A and R are true and R is the correct reason for A.

  • Both A and R are true and R is the incorrect reason for A.

1. (i)Page 388

Data: 9, 11, 15, 19, 17, 13 and 7.

Statement (1): For the given data, lower quartile is 11.

Statement (2): For data with n terms, the lower quartile is `((n+1)/4)^(th)` term, if n is odd.

  • Both the statements are true.

  • Both the statements are false.

  • Statement 1 is true, and statement 2 is false.

  • Statement 1 is false, and statement 2 is true.

1. (j)Page 388

The mean of given data is 26.

C.I. 0 - 20 20 - 40 40 - 60
f 20 x 10

Statement (1): x = 26.

Statement (2): \[26=\frac{10 \times 20+30 \times x+50 \times 10}{30+x}\]

  • Both the statements are true.

  • Both the statements are false.

  • Statement 1 is true, and statement 2 is false.

  • Statement 1 is false, and statement 2 is true.

1. (k)Page 388

For a given set of data mean = 14 and median = 15.

Statement (1): Mode = 17.

Statement (2): Mode = 3 median − 2 mean.

  • Both the statements are true.

  • Both the statements are false.

  • Statement 1 is true, and statement 2 is false.

  • Statement 1 is false, and statement 2 is true.

2.Page 389

The mean of 1, 7, 5, 3, 4 and 4 is m. The numbers 3, 2, 4, 2, 3, 3 and p have mean m – 1 and median q. Find p and q.

3.Page 389

In a malaria epidemic, the number of cases diagnosed were as follows: 

Date July  1 2 3 4 5 6 7 8 9 10 11 12
Num 5 12 20 27 46 30 31 18 11 5 0 1

On what days do the mode and upper and lower quartiles occur?

4.Page 389

The marks obtained by 120 students in a mathematics test is given below: 

Marks  No. of students 
0 – 10 5
10 – 20 9
20 – 30 16
30 – 40 22
40 – 50 26
50 – 60 18
60 – 70 11
70 – 80 6
80 – 90 4
90 – 100 3

Draw an ogive for the given distributions on a graph sheet. Use a suitable scale for your ogive. Use your ogive to estimate:

  1. the median
  2. the number of student who obtained more than 75% in test.
  3. the number of students who did not pass in the test if the pass percentage was 40.
  4. the lower quartile.
5.Page 389

Using a graph paper, draw an ogive for the following distribution which shows a record of the Weight in kilograms of 200 students. 

Weight   Frequency 
40 – 45 5
45 – 50 17
50 – 55 22
55 – 60 45
60 – 65 51
65 – 70 31
70 – 75 20
75 – 80 9

Use your ogive to estimate the following:

  1. The percentage of student weighting 55 kg or more
  2. The weight above which the heaviest 30% of the student fall
  3. The number of students who are
    1. underweight
    2. overweight, If 55.70 kg is considered as standard weight.
6.Page 389

The distribution, given below, shows the marks obtained by 25 students in an aptitude test. Find the mean, median and mode of the distribution. 

Marks obtained 5 6 7 8 9 10
No. of students  3 9 6 4 2 1
7.Page 389

The monthly income of a group of 320 employees in a company is given below:

Monthly income (thousands)  No. of employees 
6-7 20
7-8 45
8-9 65
9-10 95
10-11 60
11-12 30
12-13 5

Draw an ogive of the distribution on a graph paper taking 2 cm = Rs. 1000 on one axis and 2 cm = 50 employees on the other axis. From the graph detemine: 

  1. the median wage. 
  2. number of employee whose income is below Rs. 8,500.
  3. If salary of a senior employee is above Rs. 11,500, find the number of senior employee in the company. 
  4. the upper quartile.
8.Page 390

The mean of following numbers is 68. Find the value of ‘x’. 45, 52, 60, x, 69, 70, 26, 81 and 94. Hence, estimate the median.

9.Page 390

The marks of 10 students of a class in an examination arranged in ascending order is as follows:

13, 35, 43, 46, x, x + 4, 55, 61, 71, 80

If the median marks is 48, find the value of x. Hence, find the mode of the given data.

10.Page 390

The histogram below represents the scores obtained by 25 students in a mathematics mental test. Use the data to:

  1. Frame a frequency distribution table.
  2. To calculate mean.
  3. To determine the Modal class.

11. (a)Page 390

For the data given in the following table, find:

Class-mark Frequency
15 10
25 12
35 14
45 16
55 8
  1. mean
  2. mode (using graph)
  3. median (using grap)
11. (b)Page 390

For the data given in the following table, find:

Class-mark Frequency
35 8
40 10
45 12
50 15
55 20
60 15
  1. mean
  2. mode (using graph)
  3. median (using grap)

Case-Study Based Question

1.Page 391

On average, 80 patients get admitted into a nursing home in a day. The ages of the patients admitted and their number are as given below:

Age (in years) 10-20 20-30 30-40 40-50 50-60
No. of patients 13 23 25 14 5

Find:

  1. The average age for which maximum cases occur.
  2. The upper limit of modal class.
  3. The mean of the given data.
2.Page 391

Along with an increase in population, electricity consumption per person is also increasing nationwide.

A survey is conducted for 560 families of Mangal Pande Nagar, Meerut. The following table gives the monthly consumption of electricity of these families.

Monthly consumption (in units) 0-100 100-200 200-300 300-400 400-500
No. of families 160 120 180 60 40

Assuming that no family consumes more than 500 units of electricity, find:

  1. The mean monthly consumption.
  2. The modal monthly class.

Solutions for 24: Measure of Central Tendency (Mean, Median, Quartiles and Mode)

EXERCISE 24 (A)EXERCISE 24 (B)EXERCISE 24 (C)TEST YOURSELF
Selina solutions for Concise Mathematics [English] Class 10 ICSE chapter 24 - Measure of Central Tendency (Mean, Median, Quartiles and Mode) - Shaalaa.com

Selina solutions for Concise Mathematics [English] Class 10 ICSE chapter 24 - Measure of Central Tendency (Mean, Median, Quartiles and Mode)

Shaalaa.com has the CISCE Mathematics Concise Mathematics [English] Class 10 ICSE CISCE solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Selina solutions for Mathematics Concise Mathematics [English] Class 10 ICSE CISCE 24 (Measure of Central Tendency (Mean, Median, Quartiles and Mode)) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. Selina textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.

Concepts covered in Concise Mathematics [English] Class 10 ICSE chapter 24 Measure of Central Tendency (Mean, Median, Quartiles and Mode) are Frequency Distribution and Its Applications, Histograms, Frequency Polygon, Cumulative Frequency and Cumulative Frequency Table, Ogives (Cumulative Frequency Curve), Concepts of Statistics, Frequency Distribution and Its Applications, Histograms, Frequency Polygon, Cumulative Frequency and Cumulative Frequency Table, Ogives (Cumulative Frequency Curve), Concepts of Statistics, Frequency Distribution and Its Applications, Histograms, Frequency Polygon, Cumulative Frequency and Cumulative Frequency Table, Ogives (Cumulative Frequency Curve), Concepts of Statistics.

Using Selina Concise Mathematics [English] Class 10 ICSE solutions Measure of Central Tendency (Mean, Median, Quartiles and Mode) exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Selina Solutions are essential questions that can be asked in the final exam. Maximum CISCE Concise Mathematics [English] Class 10 ICSE students prefer Selina Textbook Solutions to score more in exams.

Get the free view of Chapter 24, Measure of Central Tendency (Mean, Median, Quartiles and Mode) Concise Mathematics [English] Class 10 ICSE additional questions for Mathematics Concise Mathematics [English] Class 10 ICSE CISCE, and you can use Shaalaa.com to keep it handy for your exam preparation.

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×